Home
Class 9
MATHS
On the sides AB and AC of triangle ABC, ...

On the sides AB and AC of triangle ABC, equilateral triangles ABD and ACE are drawn. Prove that :
(i) `angle CAD = angle BAE`
(ii) CD = BE

Answer

Step by step text solution for On the sides AB and AC of triangle ABC, equilateral triangles ABD and ACE are drawn. Prove that : (i) angle CAD = angle BAE (ii) CD = BE by MATHS experts to help you in doubts & scoring excellent marks in Class 9 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TRIANGLES

    ICSE|Exercise QUESTIONS|8 Videos
  • TRIANGLES

    ICSE|Exercise 3 MARKS QUESTIONS |11 Videos
  • TRIANGLES

    ICSE|Exercise 4 MARKS QUESTIONS |24 Videos
  • STATISTICS AND GRAPH WORK

    ICSE|Exercise TOPIC - 2 (4 Marks Questions)|14 Videos
  • TRIGONOMETRICAL RATIOS

    ICSE|Exercise EXERCISE 22(B)|50 Videos

Similar Questions

Explore conceptually related problems

On the sides AB and AC of triangle ABC, equilateral triangles ABD and ACE are drawn. Prove that : angleCAD=angleBAE

Equilateral triangles ABD and ACE are drawn on sides AB and AC respectively of a DeltaABC outside it. Prove that : (i) angleDAC= angleEAB (ii) DC = BE

The sides AB and AC of a triangle ABC are produced, and the bisectors of the external angles at B and C meet at P. Prove that if AB gt AC , then PC gt PB .

The given figure shows a parallelogram ABCD. Squares ABPQ and ADRS are drawn on sides AB and AD of the parallelogram ABCD. Prove that : (i) angle SAQ = angle ABC (ii) SQ = AC

In the following figure, ABC is an equilateral triangle and P is any point in AC, prove that : (i) BP gt PA (ii) BP gt PC

In the following figure, ABC is an equilateral triangle and P is any point in AC, prove that : (i) BP gt PA (ii) BP gt PC

The P lies on side AB of an equilateral triangle ABC. Arrange AC, AP and CP in descending order.

AD is a median of triangle ABC. Prove that : AB+AC gt 2AD

The angles A, B and C of a triangle ABC are in arithmetic progression. AB=6 and BC=7. Then AC is :

In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC. If BH perpendicular to FG, prove that : (i) DeltaEAC~=DeltaBAF . (ii) Area of the square ABDE = Area of the rectangle ARHF.