Home
Class 9
CHEMISTRY
A reaction of a type : AB+CD to AD+CD, i...

A reaction of a type : `AB+CD to AD+CD`, involves

A

no chemical change

B

decomposition of AB and CD

C

exchange of ions of AB and CD

D

combination of AB and CD

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL CHANGES AND REACTIONS

    ICSE|Exercise EXERCISE 2(C)|30 Videos

  • CHEMICAL CHANGES AND REACTIONS

    ICSE|Exercise EXERCISE 2(C)|30 Videos

  • ATOMIC STRUCTURE AND CHEMICAL BONDING

    ICSE|Exercise EXERCISE 4(D)|21 Videos

  • ICSE EXAMINATION PAPER 2020

    ICSE|Exercise Section-I|11 Videos

Similar Questions

Explore conceptually related problems

If the sides of a quadrilateral ABCD touch a circle prove that AB+CD=BC+AD.

In the adjoining figure, common tangents AB and CD to two circles intersect at P. Prove that AB=CD.

The given figure (not drawn to scale) shows two straight lines AB and CD. If equation of the line AB is : y = x + 1 and equation of line CD is : y = sqrt(3) x - 1 . Write down the inclination of lines AB and CD, also, find the angle theta between AB and CD.

Find the area of the trapezium ABCD in which AB//DC, AB = 18 cm, angleB = angleC = 90^(@) , CD = 12 cm and AD = 10 cm.

In the adjoining figure, AB = CD and AB||CD prove that (i) DeltaAOB cong DeltaDOC (ii) AD and BC bisect each other at the point O.

In the adjoining figure AB = CD and AB"||"CD prove that : (i) DeltaAOB cong DeltaDOG (ii) AD and BC bisect each other at point O.

In the figure if AB || CD and AD||BC, find angleA and angleD

ABCD is a trapezium such that AB and CD are parallel and BC bot CD . If angleADB = theta, BC = p and CD = q , then AB is equal to

In figure, common tangents AB and CD to two circles intersect at E. Prove that AB=CD.

The following figure shows a trapezium ABCD in which AB // DC. P is the mid-point of AD and PR // AB. Prove that: PR = (1)/(2)(AB + CD)

Home
Profile