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Two equal positive charges are placed at...

Two equal positive charges are placed at two corners or a square, 'the' other two corners having neglative charges or equal magnitude. Find the field intensity in the centre of the square in the two cases.

Text Solution

Verified by Experts

The correct Answer is:
`E=0; E=(q sqrt(2))/(pi epsilon_(0)a^(2))`.
If the charges are placed in Fig., the field intensity in the centre of the square will be zero.
If the charges are placed as in Fig. we find the field intensities due to the individual charges and then add up the field intensity vectors.
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Knowledge Check

  • If (-1, -1) and (3, -1) are two opposite corners of a square, the other two corners a

    A
    (2, 0), (- 2, 2)
    B
    (2, -2), (0, 2)
    C
    (3,0), (4, - 2)
    D
    None of these

  • Five identical point charges +Q are placed at the five corners of a regular hexagon of edge length a. One corner is empty. Electric field intensity at the centre of the hexagon is

    A
    Zero
    B
    `Q/(4piepsilon_0d^2)`, towards the empty corner
    C
    `Q/(4piepsilon_0d^2)`, away from the empty corner
    D
    `(5Q)/(4piepsilon_0a^2)` towards the empty corner

  • Four charges +Q, -Q, +Q, -Q are placed at the corners of a square taken in order. At the centre of the square

    A
    `E = 0, V = 0`
    B
    `E = 0, V != 0`
    C
    `E != 0, V = 0`
    D
    `E = 0, V != 0`

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