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Two equal positive charges are placed at...

Two equal positive charges are placed at two corners or a square, 'the' other two corners having neglative charges or equal magnitude. Find the field intensity in the centre of the square in the two cases.

Text Solution

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The correct Answer is:
`E=0; E=(q sqrt(2))/(pi epsilon_(0)a^(2))`.
If the charges are placed in Fig., the field intensity in the centre of the square will be zero.
If the charges are placed as in Fig. we find the field intensities due to the individual charges and then add up the field intensity vectors.
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