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1+3+5+.. . .+(2 n-1)=...

`1+3+5+.. . .+(2 n-1)=`

A

`n^(2)+1`

B

`2 n`

C

`n^(2)`

D

` n^(2)-1`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • sum_(k=1)^(5) (1^(3)+2^(3)+.. ..+k^(3))/(1+3+5+.. ..+(2 k-1))=

    A
    1: 22.5
    B
    2: 24.5
    C
    3: 28.5
    D
    4: 32.5
  • The value of ""2^n[1.3.5 ..........(2n-3)(2n-1)] is

    A
    `((2n)i)/(n!)`
    B
    `((2n)i)/(2^n)`
    C
    `(n!)/((2n)!)`
    D
    None of these
  • 1 . 3+3 . 5+5 . 7+.. . . to n terms =

    A
    1)` (n)/(5) (3 n^(2)+7 n+5)`
    B
    2)`(n)/(2)(2 n^(2)+3 n+1)`
    C
    3)`(n)/(3)(4 n^(2)+6 n-1)`
    D
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