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Ethylene glycol is used as an antifreeze...

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at `-6^@C`.
`(K_f " for " H_2O = 1*85 K "mole"^(-1) kg)`

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AI Generated Solution

To solve the problem of calculating the amount of ethylene glycol needed to prevent 4 kg of water from freezing at -6°C, we will use the formula for depression in freezing point. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the given data - Weight of solvent (water) = 4 kg - Freezing point of pure water = 0°C - Freezing point of the solution = -6°C - \( K_f \) for water = 1.85 K kg/mol - Molecular weight of ethylene glycol (C2H6O2) = 62 g/mol ...
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Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at -6^(@)C.(K_(f)" for "HH_(2)O=1.85" K mol"^(-1)"kg")

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Knowledge Check

  • 45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

    A
    273.95 K
    B
    270.95 K
    C
    370 . 95 K
    D
    373.95 K

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