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The bond dissociation energies of two O-...

The bond dissociation energies of two O-H bond in water are: `H_2O(g)rarr H(g)+OH(g), Delta H=497.8 KJ mol^(-1)`
`OH(g)rarr H(g)+O(g), Delta H=428.5 KJ mol^(-1)` bond energy of O-H bond is

A

`463.15 KJ mol^(-1)`

B

`926.30KJ mol^(-1)`

C

`231.05 KJ mol^(-1)`

D

`1390.45KJ mol^(-1)`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • H_2(g)rarr2H(g), DeltaH=104.2 kcal . The bond energy of H-H bond is

    A
    104.2 kcal
    B
    208.4 kcal
    C
    52.1 kcal
    D
    zero

  • The enthalpy change at 298 K for decomposition is given in the following two steps Step 1: H_2O(g) to H(g) + OH(g), triangleH = 498 kJ mol^-1 Step II: OH(g) to H(g) + O(g), triangleH 428 kJ mol^-1 The bond enthalpy of the O-H bond is

    A
    `498 kJ mol^-1`
    B
    `463 kJ mol^-1`
    C
    `428 kJ mol^-1`
    D
    `70 kJ mol^-1`

  • Using the data provided calculate the multiple bond energy (KJ mol^(-)) of a C-=C bond in c_2H_2 consider the bond energy of a C-H bond is 350 KJ mol^(-1) 2C(s)+H_2(g)rarr C_2H_2(g), Delta H=225KJ mol^(-1) 2C(s)rarr2 C(g), Delta H=1410 KJ mol^(-1) H_2(g)rarr 2H(g), Delta H=330KJ mol^(-1)

    A
    1165
    B
    837
    C
    865
    D
    815

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