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If the ionization energy of Li^(+2) is 1...

If the ionization energy of `Li^(+2)` is `19.6xx10^(-18)` J per atom then energy of `Be^(+3)` ion in the second stationary state is

A

`-4.9xx10^-18J`

B

`-19.6xx10^-18J`

C

`-11.025xx10^-18J`

D

none of these

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Ionisation energy of He^+ is 19.6xx10^(-18) J atom^(-1) The energy of the first stationary state (n=1) of Li^(2+)?

    A
    `4.41xx10^(-16) Jatom^(-1)`
    B
    `-4.41xx10^(-17) Jatom^(-1)`
    C
    `-2.2xx10^(-15) Jatom^(-1)`
    D
    `8.82xx10^(-17) Jatom^(-1)`

  • The ionisation enthalpy of hydrogen atom is 1.312xx10^(6)J*mol^(-1) . The energy required to excited the electron in the atom from n=1 to n=2 is-

    A
    `7.56xx10^(5)J*mol^(-1)`
    B
    `9.84xx10^(5)J*mol^(-1)`
    C
    `8.51xx10^(5)J*mol^(-1)`
    D
    `6.56xx10^(5)J*mol^(-1)`

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