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When a equimolar mixture of Cu2S and ...

When a equimolar mixture of `Cu_2S` and CuS is titrated with `Ba(MnO_4)_2` in acidic medium, the final product contains `Cu^(2+)S0_2` and `Mn^(2+)`. If the mol. wt. of `Cu_2S,CuS` and `Ba(MnO_4)_2` are `M_1 M_2` and `M_3` respectively then:

A

eq. wt of `Cu_2S` is `M_1/8`

B

eq. wt od CuS is `M_2/6`

C

eq. wt. of `Ba(MnO_4)_2` is `M_3/5`

D

`Cu_2S` nad CuS both have same equivalents in mixture

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Knowledge Check

  • n-factor of Ba (MnO_4)_2 in acidic medium is :

    A
    2
    B
    6
    C
    10
    D
    None of these

  • Heating a mixture of Cu_(2)O and Cu_(2)S gives -

    A
    `Cu_(2)SO_(3)`
    B
    `CuO+CuS`
    C
    `Cu+SO_(3)`
    D
    `Cu+SO_(2)`

  • For the following balanced redox reaction, 2MnO_4^(-)+4H^++BR_2rarr2Mn^(2+)+2BrO_3^(-)+2H_2O if the molecular wt. of MnO_4^(-)Br_2 be M_xM_y respectively, then

    A
    equivalent wt. of `MnO_4^(-)` is `(M_x)/5`
    B
    equivalent wt. of `Br_2` is `(M_y)/10`
    C
    the n-factor ratio of `Mn^(2+)` to `BrO_3^(-)` is 1 : 1
    D
    none of these

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