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A particle of charge q and mass m starts...

A particle of charge q and mass m starts moving from the origin under the action of an electric field `vecE=E_0 hat i` and `vec B=B_0 hat i` with velocity `vec v=v_0 hat j`. The speed of the particle will become `2v_0` after a time

A

`t=(2mv_0)/(qE)`

B

`t=(2Bq)/(mv_0)`

C

`t=(sqrt3Bq)/(mv_0)`

D

`t=(sqrt3mv_0)/(qE)`

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A particle of charge q and mass m starts moving from the origin with a velocity vec(v) doteq v_(0) hat(j) under the action of an electric field vec(E)=E_(5) bar(i) and magnetic field vec(B)=B_(0) vec(i) The speed of the particle will become 2 v_(0) aftet a time t=(sqrt(x) m w_(0))/(q E_(0)) . Find the value of x .

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Knowledge Check

  • A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

    A
    `t=(2mv_0)/(qE)`
    B
    `t=(2Bq)/(mv_0)`
    C
    `t=(sqrt3Bq)/(mv_0)`
    D
    `t=(sqrt2mv_0)/(qE)`

  • A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hatj . The speed of the particle will becomes (sqrt(5))/(2) v_0 after a time

    A
    `(mv_(0))/(qE_(0))`
    B
    `(mv_(0))/(2qE_(0))`
    C
    `(sqrt3mv_(0))/(2qE_(0))`
    D
    `(sqrt5mv_(0))/(2qE_(0))`

  • A particle of charge q, mass m starts moving from origin under the action of an electric field vecE = E_0 hati and magnetic field vecB = B_0 hatk . Its velocity at ( x,0,0) is v_0 ( 6 hati + 8 j hatj) . The value of x is :

    A
    `(25 mv_(0)^(2))/( qE_0)`
    B
    `(100 mv_(0)^(2))/(qB_0)`
    C
    `(50 mV_(0)^(2))/( qE_0)`
    D
    `(14 mv_(0)^(2))/( q E_0)`

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