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Show.that the de-Broglie wavelength lamb...

Show.that the de-Broglie wavelength `lambda` of electrons of energy E is given by the relation, `lambda = h/sqrt(2mE)`.

Answer

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Show that the de Broglie wavelength of electron of energy K is given by lamda = (h)/(sqrt(2mK)) .

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Knowledge Check

  • Statement I: If a stationary electron is accelerated with a potential difference of 1V, its de Broglie wavelength becomes 12.27 Å approximately. Statement II: The relation between the de Broglie wavelength lamda and the accelerating potential V of an electron is given by lamda = (12.27)/(V) Å

    A
    Statement I is true, statement II is true, statement II is a correct explanation for statement I
    B
    Statement I is true, statement II is true, statement II is not a correct explanation for statement I
    C
    statement I is true, statement II is false
    D
    statement I is false, statement II is true

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