find the de Broglie's wavelength.

The de Broglie wavelength of a moving electron is 1 Å . What is its velocity?

A proton and an electron have same de Broglie wavelength. Which one has higher kinetic energy?

Energy of a photon = E , kinetic energy of a proton is also the same as energy of the photon. Corresponding wavelength of the photon and de Broglie wavelength of the proton are lamda_(1) and lamda_(2) , respectively. What is the relation between E and the ratio of lamda_(1) and lamda_(2) ?

If wavelength (lamda) of a photon and de Broglie wavelength of an electron are same, then show that the energy of the photon is (2 lamda mc)/(h) times the kinetic energy of the electron. Here, m, c and h have their usual meanings

The de Broglie wave length of an electron of velocity 1.5×10^8 m/s is equal to that of photon. The ratio of the kinetic energy of electron and photon will be—

Write down the relationship between wavelength and energy of a photon? If a proton and an alpha particle is moving with the same kinetic energy, then what is the relationbetween their de Broglie wave length?

Calculate the de Broglie wavelength of an electron of kinetic energy 500 eV.

The de Broglie wavelength of an electron is the same as that of a 50 keV X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is the energy equivalent of electron mass is 0.5 MeV)