Sucrose in water is dextrorotatory, `[alpha]_(D)=+66.4^(@)` when boiled with dil. HCl, the solution becomes leavorotatory , `[alpha]_(D)=-39.9^(@)`,. In this process the sucrose breaks into

Options

A. L-glucose +D-fructose
B. L-glucose+L-fructose
C. D-glucose+D-fructose
D. D-glucose+L-fructose

Explanation

To solve the question regarding the hydrolysis of sucrose when boiled with dilute HCl, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Sucrose**:
- Sucrose is a disaccharide composed of two monosaccharides: glucose and fructose. Its molecular formula is C12H22O11.

2. **Dextrorotatory Nature of Sucrose**:
- In its original state, sucrose is dextrorotatory, meaning it rotates plane-polarized light to the right. The specific rotation of sucrose is given as \([α]_D = +66.4^\circ\).

3. **Effect of Dilute HCl**:
- When sucrose is boiled with dilute hydrochloric acid (HCl), hydrolysis occurs. This means that sucrose breaks down into its constituent monosaccharides.

4. **Products of Hydrolysis**:
- The hydrolysis of sucrose results in the formation of D-glucose and D-fructose. Both of these monosaccharides have the same molecular formula, C6H12O6.

5. **Levorotatory Nature of the Products**:
- After hydrolysis, the solution becomes levorotatory, which means it rotates plane-polarized light to the left. The specific rotation of the resulting mixture is \([α]_D = -39.9^\circ\).

6. **Specific Rotations of the Products**:
- The specific rotation of D-glucose is \([α]_D = +52.5^\circ\) and that of D-fructose is \([α]_D = -92.8^\circ\). The overall rotation of the mixture being negative indicates that the contribution from D-fructose is greater than that from D-glucose.

7. **Conclusion**:
- Therefore, the hydrolysis of sucrose in the presence of dilute HCl leads to the formation of D-glucose and D-fructose, resulting in the observed change in optical rotation.

### Final Answer:
The sucrose breaks into **D-glucose and D-fructose**.