Home
Class 12
CHEMISTRY
The correct order of N-O bond lengths in...

The correct order of N-O bond lengths in NO, `NO_2^- , NO_3^-` and `N_2O_4` is

A

`N_2O_4 gt NO_2^(-) gt NO_3^(-) gt NO`

B

`NO gt NO_3^(-) gt N_2O_4 gt NO_2^-`

C

`NO_3^(-) gt NO_2^(-) gt N_2O_4 gt NO`

D

`NO gt N_2O_4 gt NO_2^(-) gt NO_3^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of N-O bond lengths in the molecules NO, NO₂⁻, NO₃⁻, and N₂O₄, we will follow these steps: ### Step 1: Determine the Bond Order for Each Molecule The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonds}}{\text{Number of bonding sites}} \] #### 1.1 For N₂O₄: - Structure: N₂O₄ has a central nitrogen atom bonded to two oxygen atoms with double bonds and two oxygen atoms with single bonds. - Number of bonds with oxygen: 6 (3 double bonds) - Number of oxygen atoms: 4 - Bond Order: \[ \text{Bond Order} = \frac{6}{4} = 1.5 \] #### 1.2 For NO₂⁻: - Structure: NO₂⁻ has a nitrogen atom bonded to two oxygen atoms, one with a double bond and one with a single bond, and carries a negative charge. - Number of bonds with oxygen: 3 (1 double bond and 1 single bond) - Number of oxygen atoms: 2 - Bond Order: \[ \text{Bond Order} = \frac{3}{2} = 1.5 \] #### 1.3 For NO₃⁻: - Structure: NO₃⁻ has a nitrogen atom bonded to three oxygen atoms, one with a double bond and two with single bonds, and carries a negative charge. - Number of bonds with oxygen: 4 (1 double bond and 2 single bonds) - Number of oxygen atoms: 3 - Bond Order: \[ \text{Bond Order} = \frac{4}{3} \approx 1.33 \] #### 1.4 For NO: - Structure: NO has a nitrogen atom bonded to one oxygen atom with a triple bond. - Number of bonds with oxygen: 3 (1 triple bond) - Number of oxygen atoms: 1 - Bond Order: \[ \text{Bond Order} = \frac{3}{1} = 3.0 \] ### Step 2: Compare Bond Orders and Infer Bond Lengths The bond order is inversely proportional to bond length; higher bond order means shorter bond length. - NO: Bond Order = 3.0 (shortest bond length) - N₂O₄: Bond Order = 1.5 - NO₂⁻: Bond Order = 1.5 - NO₃⁻: Bond Order ≈ 1.33 (longest bond length) ### Conclusion Based on the bond orders, we can conclude the order of N-O bond lengths from shortest to longest: 1. NO (shortest bond length) 2. N₂O₄ and NO₂⁻ (same bond length) 3. NO₃⁻ (longest bond length) Thus, the correct order of N-O bond lengths is: **NO < N₂O₄ = NO₂⁻ < NO₃⁻**

To determine the correct order of N-O bond lengths in the molecules NO, NO₂⁻, NO₃⁻, and N₂O₄, we will follow these steps: ### Step 1: Determine the Bond Order for Each Molecule The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonds}}{\text{Number of bonding sites}} \] #### 1.1 For N₂O₄: - Structure: N₂O₄ has a central nitrogen atom bonded to two oxygen atoms with double bonds and two oxygen atoms with single bonds. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The correct order of S-O bond length is :

The correct order of O-O bond length in O_2,H_2 O and O_3 .

The correct order of increasing C-O bond lengths in CO, CO_3^(2-) and CO_2 is :

The correct order of o^(-) bond lengths in ClO^(-), ClO_(2)^(-), ClO_(3)^(-) and ClO_(4)^(-) is

The correct order of O - O bond length in O_(2)H_(2)O_(2) and O_(3) is

The correct order of increasing C- O bond length of CO, CO_(3) ^(-2) and CO_(2) is :-

The correct order of increasig C-O bond length of CO, CO_(3)^(2-), CO_(2) is

The bond order of the N-O bonds in NO_3^- ion is

Bond order of N-O bonds in nitrate ion is

In nitromethane two N-O bond lengths are :