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The correct order of N-O bond lengths in...

The correct order of N-O bond lengths in NO, `NO_2^- , NO_3^-` and `N_2O_4` is

A

`N_2O_4 gt NO_2^(-) gt NO_3^(-) gt NO`

B

`NO gt NO_3^(-) gt N_2O_4 gt NO_2^-`

C

`NO_3^(-) gt NO_2^(-) gt N_2O_4 gt NO`

D

`NO gt N_2O_4 gt NO_2^(-) gt NO_3^(-)`

Text Solution

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The correct Answer is:
To determine the correct order of N-O bond lengths in the molecules NO, NO₂⁻, NO₃⁻, and N₂O₄, we will follow these steps: ### Step 1: Determine the Bond Order for Each Molecule The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonds}}{\text{Number of bonding sites}} \] #### 1.1 For N₂O₄: - Structure: N₂O₄ has a central nitrogen atom bonded to two oxygen atoms with double bonds and two oxygen atoms with single bonds. - Number of bonds with oxygen: 6 (3 double bonds) - Number of oxygen atoms: 4 - Bond Order: \[ \text{Bond Order} = \frac{6}{4} = 1.5 \] #### 1.2 For NO₂⁻: - Structure: NO₂⁻ has a nitrogen atom bonded to two oxygen atoms, one with a double bond and one with a single bond, and carries a negative charge. - Number of bonds with oxygen: 3 (1 double bond and 1 single bond) - Number of oxygen atoms: 2 - Bond Order: \[ \text{Bond Order} = \frac{3}{2} = 1.5 \] #### 1.3 For NO₃⁻: - Structure: NO₃⁻ has a nitrogen atom bonded to three oxygen atoms, one with a double bond and two with single bonds, and carries a negative charge. - Number of bonds with oxygen: 4 (1 double bond and 2 single bonds) - Number of oxygen atoms: 3 - Bond Order: \[ \text{Bond Order} = \frac{4}{3} \approx 1.33 \] #### 1.4 For NO: - Structure: NO has a nitrogen atom bonded to one oxygen atom with a triple bond. - Number of bonds with oxygen: 3 (1 triple bond) - Number of oxygen atoms: 1 - Bond Order: \[ \text{Bond Order} = \frac{3}{1} = 3.0 \] ### Step 2: Compare Bond Orders and Infer Bond Lengths The bond order is inversely proportional to bond length; higher bond order means shorter bond length. - NO: Bond Order = 3.0 (shortest bond length) - N₂O₄: Bond Order = 1.5 - NO₂⁻: Bond Order = 1.5 - NO₃⁻: Bond Order ≈ 1.33 (longest bond length) ### Conclusion Based on the bond orders, we can conclude the order of N-O bond lengths from shortest to longest: 1. NO (shortest bond length) 2. N₂O₄ and NO₂⁻ (same bond length) 3. NO₃⁻ (longest bond length) Thus, the correct order of N-O bond lengths is: **NO < N₂O₄ = NO₂⁻ < NO₃⁻**

To determine the correct order of N-O bond lengths in the molecules NO, NO₂⁻, NO₃⁻, and N₂O₄, we will follow these steps: ### Step 1: Determine the Bond Order for Each Molecule The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonds}}{\text{Number of bonding sites}} \] #### 1.1 For N₂O₄: - Structure: N₂O₄ has a central nitrogen atom bonded to two oxygen atoms with double bonds and two oxygen atoms with single bonds. ...
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