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Mark the incorrect statement in the foll...

Mark the incorrect statement in the following .

A

The bond order in the species `O_2, O_2^+` and `O_2^-` decreases as `O_2^(+) gt O_2 gt O_2^-`

B

The bond energy in a diatomic molecule always increases when an electron is lost

C

Electrons in antibonding MO contribute to repulsion between two atoms

D

With increase in bond order, bond length decreases and bond strength increases.

Text Solution

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The correct Answer is:
To solve the question of identifying the incorrect statement among the given options, we will analyze each option step-by-step. ### Step 1: Analyze Option A **Statement**: The bond order in the species O2, O2⁺, and O2⁻ decreases as O2⁺ > O2 > O2⁻. 1. **Determine the bond order for O2**: - O2 has 16 electrons. - The molecular orbital (MO) configuration is: \[ \sigma_{1s}^2 \sigma_{1s}^*^2 \sigma_{2s}^2 \sigma_{2s}^*^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^*^1 \pi_{2p_y}^*^1 \] - Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 - Bond order for O2 = (10 - 6) / 2 = 2. 2. **Determine the bond order for O2⁺**: - O2⁺ has one less electron than O2. - Remove one electron from the antibonding orbitals: - Bond order for O2⁺ = (10 - 5) / 2 = 2.5. 3. **Determine the bond order for O2⁻**: - O2⁻ has one more electron than O2. - Add one electron to the antibonding orbitals: - Bond order for O2⁻ = (10 - 7) / 2 = 1.5. 4. **Conclusion for Option A**: - The bond order increases as O2⁺ (2.5) > O2 (2) > O2⁻ (1.5). - Thus, Option A is **correct**. ### Step 2: Analyze Option B **Statement**: The bond energy in a diatomic molecule always increases when an electron is lost. 1. **Evaluate the statement**: - This statement is too absolute with the word "always". - For example, in the case of O2 to O2⁺, the bond order increases, and thus the bond energy increases. - However, in the case of N2 to N2⁺, the bond order decreases, leading to a decrease in bond energy. 2. **Conclusion for Option B**: - Since bond energy may either increase or decrease when an electron is lost, this statement is **incorrect**. ### Step 3: Analyze Option C **Statement**: Electrons in antibonding MOs contribute to repulsion between two atoms. 1. **Evaluate the statement**: - Electrons in antibonding molecular orbitals do indeed contribute to repulsion between the two atoms. - This statement is **correct**. ### Step 4: Analyze Option D **Statement**: With an increase in bond order, bond length decreases and bond energy increases. 1. **Evaluate the statement**: - There is an inverse relationship between bond order and bond length (higher bond order = shorter bond length). - Higher bond order also correlates with higher bond energy. - This statement is **correct**. ### Final Conclusion The incorrect statement among the options is **Option B**.

To solve the question of identifying the incorrect statement among the given options, we will analyze each option step-by-step. ### Step 1: Analyze Option A **Statement**: The bond order in the species O2, O2⁺, and O2⁻ decreases as O2⁺ > O2 > O2⁻. 1. **Determine the bond order for O2**: - O2 has 16 electrons. - The molecular orbital (MO) configuration is: ...
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