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Equal moles of hydrogen and oxygen gases...

Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape ?

A

`1//4`

B

`3//8`

C

`1//2`

D

`1//8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. ### Step-by-Step Solution: 1. **Identify the Molar Masses**: - Molar mass of Hydrogen (H₂) = 2 g/mol - Molar mass of Oxygen (O₂) = 32 g/mol 2. **Apply Graham's Law**: - According to Graham's law, the rate of effusion (R) is given by: \[ R \propto \frac{1}{\sqrt{M}} \] - Where M is the molar mass of the gas. 3. **Set Up the Ratios**: - Let \( R_{H_2} \) be the rate of effusion of hydrogen and \( R_{O_2} \) be the rate of effusion of oxygen. - According to Graham's law: \[ \frac{R_{H_2}}{R_{O_2}} = \frac{\sqrt{M_{O_2}}}{\sqrt{M_{H_2}}} \] - Substituting the molar masses: \[ \frac{R_{H_2}}{R_{O_2}} = \frac{\sqrt{32}}{\sqrt{2}} = \frac{4}{1} = 4 \] - This means that hydrogen effuses 4 times faster than oxygen. 4. **Determine the Time for Hydrogen to Escape**: - Let’s assume that in a certain time \( t \), half of the hydrogen escapes. Therefore, if we denote the initial moles of hydrogen as 1 mole, then: \[ \text{Moles of } H_2 \text{ escaped} = \frac{1}{2} \text{ mole} \] 5. **Calculate Moles of Oxygen Escaped in the Same Time**: - Since the rate of hydrogen is 4 times that of oxygen, if \( x \) moles of oxygen escape in the same time \( t \), we can set up the equation: \[ \frac{1/2}{x} = 4 \implies x = \frac{1/2}{4} = \frac{1}{8} \text{ moles} \] 6. **Calculate the Fraction of Oxygen Escaped**: - The fraction of oxygen that escapes is given by: \[ \text{Fraction of } O_2 \text{ escaped} = \frac{\text{Moles of } O_2 \text{ escaped}}{\text{Initial moles of } O_2} = \frac{1/8}{1} = \frac{1}{8} \] ### Final Answer: The fraction of oxygen that escapes in the time required for one-half of the hydrogen to escape is \( \frac{1}{8} \).

To solve the problem, we will use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. ### Step-by-Step Solution: 1. **Identify the Molar Masses**: - Molar mass of Hydrogen (H₂) = 2 g/mol - Molar mass of Oxygen (O₂) = 32 g/mol ...
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