Which compound has planar structure:

Options

A. `XeF_(4)`
B. `XeOF_(2)`
C. `XeO_(2)F_(2)`
D. `XeO_(4)`

Answer

To determine which compound has a planar structure among the given options (XeF4, XeOF2, XeO2F2, and XeO4), we will analyze the hybridization and molecular geometry of each compound step by step.

### Step 1: Analyze XeF4
1. **Electronic Configuration of Xenon (Xe)**:
- Atomic number = 54
- Configuration: [Kr] 4d10 5s2 5p6

2. **Hybridization**:
- In XeF4, xenon uses its 5s and 5p orbitals for bonding.
- One of the 5p electrons is promoted to an empty 5d orbital.
- Thus, the hybridization is **sp³d²**.

3. **Geometry**:
- The ideal geometry for sp³d² hybridization is octahedral.
- However, XeF4 has 4 bonding pairs (from F) and 2 lone pairs on Xe.
- The presence of 2 lone pairs leads to a **square planar** structure.

### Step 2: Analyze XeOF2
1. **Hybridization**:
- In XeOF2, xenon forms bonds with one oxygen (double bond) and two fluorine atoms.
- The hybridization is **sp³d**.

2. **Geometry**:
- The ideal geometry for sp³d hybridization is trigonal bipyramidal.
- However, due to the presence of one lone pair and the arrangement of the bonds, the structure becomes **bent (T-shaped)**, which is not planar.

### Step 3: Analyze XeO2F2
1. **Hybridization**:
- In XeO2F2, xenon forms two double bonds with oxygen and two single bonds with fluorine.
- The hybridization is also **sp³d**.

2. **Geometry**:
- The ideal geometry for sp³d hybridization is trigonal bipyramidal.
- With one lone pair present, the structure distorts to a **seesaw shape**, which is again not planar.

### Step 4: Analyze XeO4
1. **Hybridization**:
- In XeO4, xenon forms four double bonds with oxygen.
- The hybridization is **sp³**.

2. **Geometry**:
- The ideal geometry for sp³ hybridization is tetrahedral.
- Since there are no lone pairs, the shape remains **tetrahedral**, which is not planar.

### Conclusion
Based on the analysis:
- **XeF4** has a square planar structure, which is planar.
- **XeOF2** has a T-shaped structure, which is not planar.
- **XeO2F2** has a seesaw shape, which is not planar.
- **XeO4** has a tetrahedral shape, which is not planar.

Thus, the compound with a planar structure is **XeF4**.