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Assume each reaction is carried out in a...

Assume each reaction is carried out in an open container. For which reaction will `DeltaH` = `DeltaE` ?

A

`H_(2)(g) + Br_(2)(g) → 2HBr(g)`

B

`C(s) + 2H_(2)O(g) → 2H_(2)(g) + CO_(2)(g)`

C

`PCl_(5)(g)→ PCl_(3)(g) + Cl_(2)(g)`

D

`2CO(g)+O_(2)(g)to2CO_(2)(g)`

Text Solution

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The correct Answer is:
To determine for which reaction ΔH = ΔE, we need to analyze the relationship between the change in enthalpy (ΔH) and the change in internal energy (ΔE). The relationship is given by the equation: \[ \Delta H = \Delta E + \Delta N_{g} RT \] Where: - ΔN_g = moles of gaseous products - moles of gaseous reactants - R = universal gas constant - T = temperature in Kelvin For ΔH to equal ΔE, the term ΔN_g RT must be zero. This implies that: \[ \Delta N_{g} = 0 \] This means that the number of moles of gaseous products must equal the number of moles of gaseous reactants. ### Step-by-step Solution: 1. **Identify the reactions**: We need to examine each reaction provided to determine the moles of gaseous reactants and products. 2. **Calculate ΔN_g for each reaction**: - **Reaction A**: - Reactants: 2 moles of H2O (g) + 2 moles of HBr (g) → Total = 2 + 2 = 4 moles (reactants) - Products: (Assuming products are also gaseous) - ΔN_g = moles of gaseous products - moles of gaseous reactants = 0 (if products are also 4 moles) - **Reaction B**: - Reactants: 2 moles of H2O (g) + 2 moles of HBr (g) → Total = 2 + 2 = 4 moles (reactants) - Products: 2 moles of H2O (g) + 1 mole of HBr (g) → Total = 2 + 1 = 3 moles (products) - ΔN_g = 3 - 4 = -1 - **Reaction C**: - Reactants: PCl5 (g) → Total = 1 mole (reactants) - Products: 2 moles of Cl2 (g) → Total = 2 moles (products) - ΔN_g = 2 - 1 = 1 - **Reaction D**: - Reactants: 3 moles of gaseous reactants → Total = 3 moles (reactants) - Products: 2 moles of gaseous products → Total = 2 moles (products) - ΔN_g = 2 - 3 = -1 3. **Determine which reaction has ΔN_g = 0**: - From the calculations: - Reaction A has ΔN_g = 0. - Reactions B, C, and D do not have ΔN_g = 0. 4. **Conclusion**: The only reaction for which ΔH = ΔE is Reaction A. ### Final Answer: The reaction for which ΔH = ΔE is **Reaction A**.

To determine for which reaction ΔH = ΔE, we need to analyze the relationship between the change in enthalpy (ΔH) and the change in internal energy (ΔE). The relationship is given by the equation: \[ \Delta H = \Delta E + \Delta N_{g} RT \] Where: - ΔN_g = moles of gaseous products - moles of gaseous reactants ...
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