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The oxidation number of the underlined a...

The oxidation number of the underlined atom in the following species. Identify the incorrect option.

A

`Cu_2underlineO` is -1

B

`underlineClO_3^-` is +5

C

K_2underline(Cr)_2O_7` is +6

D

`Hunderline(Au)Cl_4` is +3

Text Solution

AI Generated Solution

The correct Answer is:
To determine the incorrect option regarding the oxidation number of the underlined atom in the given species, we will analyze each option step by step. ### Step 1: Analyze Cu2O - **Identify the species**: Cu2O - **Identify the underlined atom**: Oxygen (O) - **Assign oxidation states**: Oxygen typically has an oxidation state of -2. - **Set up the equation**: Let the oxidation state of copper (Cu) be \( x \). The equation based on the compound's neutrality: \[ 2x + (-2) = 0 \] Solving for \( x \): \[ 2x - 2 = 0 \implies 2x = 2 \implies x = +1 \] - **Conclusion**: The oxidation state of Cu is +1 and for O is -2. However, if the question states the oxidation state of oxygen as -1, this is incorrect. ### Step 2: Analyze ClO3^- - **Identify the species**: ClO3^- - **Identify the underlined atom**: Chlorine (Cl) - **Assign oxidation states**: Oxygen has an oxidation state of -2. - **Set up the equation**: Let the oxidation state of chlorine be \( x \). The equation based on the charge of the ion: \[ x + 3(-2) = -1 \] Solving for \( x \): \[ x - 6 = -1 \implies x = +5 \] - **Conclusion**: The oxidation state of Cl is +5, which is correct as per the given option. ### Step 3: Analyze K2Cr2O7 - **Identify the species**: K2Cr2O7 - **Identify the underlined atom**: Chromium (Cr) - **Assign oxidation states**: Oxygen has an oxidation state of -2. - **Set up the equation**: Let the oxidation state of chromium be \( x \). The equation based on the charge of the compound: \[ 2(+1) + 2x + 7(-2) = 0 \] Solving for \( x \): \[ 2 + 2x - 14 = 0 \implies 2x - 12 = 0 \implies 2x = 12 \implies x = +6 \] - **Conclusion**: The oxidation state of Cr is +6, which is correct as per the given option. ### Step 4: Analyze AuCl4^- - **Identify the species**: AuCl4^- - **Identify the underlined atom**: Gold (Au) - **Assign oxidation states**: Chlorine has an oxidation state of -1. - **Set up the equation**: Let the oxidation state of gold be \( x \). The equation based on the charge of the ion: \[ x + 4(-1) = -1 \] Solving for \( x \): \[ x - 4 = -1 \implies x = +3 \] - **Conclusion**: The oxidation state of Au is +3, which is correct as per the given option. ### Final Conclusion The incorrect option is **option A** (Cu2O), where the oxidation state of oxygen was incorrectly stated as -1 instead of -2.
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