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The pth, (2p)th and (4p)th terms of an A...

The pth, `(2p)th` and `(4p)th` terms of an AP, are in GP, then find the common ratio of GP.

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To solve the problem, we need to find the common ratio of a geometric progression (GP) formed by the \( p \)th, \( 2p \)th, and \( 4p \)th terms of an arithmetic progression (AP). ### Step-by-Step Solution: 1. **Define the terms of the AP**: The general term of an AP can be expressed as: \[ T_n = a + (n-1)d ...
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ARIHANT MATHS ENGLISH-SEQUENCES AND SERIES-Exercise (Subjective Type Questions)
  1. The pth, (2p)th and (4p)th terms of an AP, are in GP, then find the co...

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  2. Find the sum of n terms of the series (a+b)+(a^(2)+ab+b^(2))+(a^(3)+a^...

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  3. The sequence of odd natural numbers is divided into groups 1,3,5,7,9,1...

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  4. Let a,b,c are respectively the sums of the first n terms, the next n t...

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  5. If the first four terms of an arithmetic sequence are a,2a,b and (a-6-...

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  6. If 1/1^2+1/2^2+1/3^2+...oo=pi^2/6 then value of 1-1/2^2+1/3^2-1/4^2+.....

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  7. If the arithmetic mean of a(1),a(2),a(3),"........"a(n) is a and b(1),...

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  8. If a(1),a(2),a(3),"........" is an arithmetic progression with common ...

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  9. If t(1)=1,t(r )-t( r-1)=2^(r-1),r ge 2, find sum(r=1)^(n)t(r ).

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  10. Prove that I(1),I(2),I(3)"..." form an AP, if I(n)=int(0)^(pi)(sin...

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  11. Consider the sequence S=7+13+21+31+".....+"T(n) , find the value of T(...

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  12. Find value of (x+(1)/(x))^(3)+(x^(2)+(1)/(x^(2)))^(3)+"........"+(x^(n...

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  13. If the sequence a1, a2, a3,....... an ,dot forms an A.P., then prove ...

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  14. If three unequel numbers are in HP and their squares are in AP, show ...

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  15. Ifa(1),a(2),a(3),"........",a(n) are in AP with a(1)=0, prove that (a(...

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  16. Balls are arranged in rows to form an equilateral triangle. The first ...

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  17. If theta(1),theta(2),theta(2), theta(3),"…………" Theta(n) are in AP w...

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  18. Show that,(1+5^(-1))(1+5^(-2))(1+5^(-4))(1+5^(-8))"....."(1+5^(-2n))= ...

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  19. Evaluate S=sum(n=0)^n(2^n)/((a^(2^n)+1) (where a>1).

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  20. Find the sum of the series :tan^- 1(1/3)+tan^- 1(2/9)+....+tan^- 1((2^...

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