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If omega is a cube root of unity but not...

If `omega` is a cube root of unity but not equal to 1, then minimum value of `abs(a+bomega+comega^(2))`, (where a,b and c are integers but not all equal ), is

A

0

B

`sqrt(3)/2`

C

1

D

2

Text Solution

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The correct Answer is:
To find the minimum value of \( |a + b\omega + c\omega^2| \), where \( \omega \) is a cube root of unity (not equal to 1) and \( a, b, c \) are integers but not all equal, we can follow these steps: ### Step 1: Understand the properties of cube roots of unity The cube roots of unity are given by: \[ \omega = e^{2\pi i / 3} = -\frac{1}{2} + i\frac{\sqrt{3}}{2} \] and \[ \omega^2 = e^{-2\pi i / 3} = -\frac{1}{2} - i\frac{\sqrt{3}}{2} \] We also know that: \[ 1 + \omega + \omega^2 = 0 \quad \text{or} \quad \omega^2 = -1 - \omega \] ### Step 2: Rewrite the expression We need to find the minimum value of: \[ |a + b\omega + c\omega^2| \] Using the property \( \omega^2 = -1 - \omega \), we can rewrite the expression: \[ |a + b\omega + c(-1 - \omega)| = |(a - c) + (b - c)\omega| \] ### Step 3: Set new variables Let: \[ x = a - c \quad \text{and} \quad y = b - c \] Thus, we need to minimize: \[ |x + y\omega| \] ### Step 4: Calculate the modulus The modulus can be expressed as: \[ |x + y\omega| = |x + y\left(-\frac{1}{2} + i\frac{\sqrt{3}}{2}\right)| \] This can be simplified to: \[ |x - \frac{y}{2} + i\frac{y\sqrt{3}}{2}| \] Using the formula for the modulus of a complex number: \[ |z| = \sqrt{(\text{Re}(z))^2 + (\text{Im}(z))^2} \] we have: \[ |x - \frac{y}{2} + i\frac{y\sqrt{3}}{2}| = \sqrt{\left(x - \frac{y}{2}\right)^2 + \left(\frac{y\sqrt{3}}{2}\right)^2} \] ### Step 5: Simplify the expression This simplifies to: \[ \sqrt{\left(x - \frac{y}{2}\right)^2 + \frac{3y^2}{4}} \] To minimize this expression, we can analyze the values of \( x \) and \( y \). ### Step 6: Consider integer values Since \( a, b, c \) are integers and not all equal, we can consider simple cases. For instance, let’s take: - \( a = 0, b = 1, c = 0 \) gives \( |0 + 1\omega + 0| = |\omega| = 1 \) - \( a = 0, b = -1, c = 0 \) gives \( |0 - 1\omega + 0| = |-\omega| = 1 \) ### Step 7: Conclusion The minimum value of \( |a + b\omega + c\omega^2| \) occurs when \( |b| = 1 \) and \( c = 0 \) or similar configurations, leading to: \[ \text{Minimum value} = 1 \] ### Final Answer The minimum value of \( |a + b\omega + c\omega^2| \) is \( \boxed{1} \).
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