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If f(x) = {{:(A+Bx^(2)",",x lt 1),(3Ax -...

If `f(x) = {{:(A+Bx^(2)",",x lt 1),(3Ax - B+2",",x ge 1):}`, then A and B, so that f(x) is differentiabl at x = 1, are

A

`-2, 3`

B

`2, -3`

C

2, 3

D

`-2, -3`

Text Solution

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The correct Answer is:
To determine the values of \( A \) and \( B \) such that the function \( f(x) \) is differentiable at \( x = 1 \), we will follow these steps: ### Step 1: Ensure Continuity at \( x = 1 \) For \( f(x) \) to be differentiable at \( x = 1 \), it must first be continuous at that point. This means that the left-hand limit as \( x \) approaches 1 must equal the right-hand limit at \( x = 1 \). The function is defined as: - \( f(x) = A + Bx^2 \) for \( x < 1 \) - \( f(x) = 3Ax - B + 2 \) for \( x \geq 1 \) Calculating the left-hand limit: \[ \lim_{x \to 1^-} f(x) = A + B(1^2) = A + B \] Calculating the right-hand limit: \[ \lim_{x \to 1^+} f(x) = 3A(1) - B + 2 = 3A - B + 2 \] Setting these two limits equal for continuity: \[ A + B = 3A - B + 2 \] ### Step 2: Solve for \( A \) and \( B \) Rearranging the equation: \[ A + B = 3A - B + 2 \] \[ A + B + B = 3A + 2 \] \[ A + 2B = 3A + 2 \] \[ 2B = 3A - A + 2 \] \[ 2B = 2A + 2 \] Dividing by 2: \[ B = A + 1 \quad \text{(Equation 1)} \] ### Step 3: Ensure Differentiability at \( x = 1 \) Next, we need to ensure that the derivatives from both sides are equal at \( x = 1 \). Calculating the derivative for \( x < 1 \): \[ f'(x) = \frac{d}{dx}(A + Bx^2) = 2Bx \] Thus, \[ \lim_{x \to 1^-} f'(x) = 2B(1) = 2B \] Calculating the derivative for \( x \geq 1 \): \[ f'(x) = \frac{d}{dx}(3Ax - B + 2) = 3A \] Thus, \[ \lim_{x \to 1^+} f'(x) = 3A \] Setting these two derivatives equal for differentiability: \[ 2B = 3A \quad \text{(Equation 2)} \] ### Step 4: Substitute Equation 1 into Equation 2 Substituting \( B = A + 1 \) into Equation 2: \[ 2(A + 1) = 3A \] Expanding: \[ 2A + 2 = 3A \] Rearranging: \[ 2 = 3A - 2A \] \[ A = 2 \] ### Step 5: Find \( B \) Now substituting \( A = 2 \) back into Equation 1: \[ B = 2 + 1 = 3 \] ### Final Answer Thus, the values of \( A \) and \( B \) that make \( f(x) \) differentiable at \( x = 1 \) are: \[ A = 2, \quad B = 3 \]
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