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For x inR - {1}, the function f(x ) sati...

For `x inR - {1}`, the function f(x ) satisfies `f(x) + 2f(1/(1-x))=x`. Find `f(2)`.

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To solve for \( f(2) \) given the equation \( f(x) + 2f\left(\frac{1}{1-x}\right) = x \), we will follow these steps: ### Step 1: Substitute \( x = 2 \) Start by substituting \( x = 2 \) into the given equation. \[ f(2) + 2f\left(\frac{1}{1-2}\right) = 2 \] This simplifies to: \[ f(2) + 2f(-1) = 2 \quad \text{(Equation 1)} \] ### Step 2: Substitute \( x = -1 \) Next, substitute \( x = -1 \) into the original equation. \[ f(-1) + 2f\left(\frac{1}{1-(-1)}\right) = -1 \] This simplifies to: \[ f(-1) + 2f\left(\frac{1}{2}\right) = -1 \quad \text{(Equation 2)} \] ### Step 3: Substitute \( x = \frac{1}{2} \) Now, substitute \( x = \frac{1}{2} \) into the original equation. \[ f\left(\frac{1}{2}\right) + 2f\left(\frac{1}{1-\frac{1}{2}}\right) = \frac{1}{2} \] This simplifies to: \[ f\left(\frac{1}{2}\right) + 2f(2) = \frac{1}{2} \quad \text{(Equation 3)} \] ### Step 4: Solve the equations Now we have three equations: 1. \( f(2) + 2f(-1) = 2 \) (Equation 1) 2. \( f(-1) + 2f\left(\frac{1}{2}\right) = -1 \) (Equation 2) 3. \( f\left(\frac{1}{2}\right) + 2f(2) = \frac{1}{2} \) (Equation 3) From Equation 1, we can express \( f(-1) \): \[ f(-1) = \frac{2 - f(2)}{2} \] ### Step 5: Substitute \( f(-1) \) into Equation 2 Substituting \( f(-1) \) into Equation 2: \[ \frac{2 - f(2)}{2} + 2f\left(\frac{1}{2}\right) = -1 \] Multiply through by 2 to eliminate the fraction: \[ 2 - f(2) + 4f\left(\frac{1}{2}\right) = -2 \] This simplifies to: \[ 4f\left(\frac{1}{2}\right) = f(2) - 4 \quad \text{(Equation 4)} \] ### Step 6: Substitute \( f\left(\frac{1}{2}\right) \) into Equation 3 Now substitute \( f\left(\frac{1}{2}\right) \) from Equation 4 into Equation 3: From Equation 4, we have: \[ f\left(\frac{1}{2}\right) = \frac{f(2) - 4}{4} \] Substituting this into Equation 3: \[ \frac{f(2) - 4}{4} + 2f(2) = \frac{1}{2} \] Multiply through by 4 to eliminate the fraction: \[ f(2) - 4 + 8f(2) = 2 \] Combine like terms: \[ 9f(2) - 4 = 2 \] ### Step 7: Solve for \( f(2) \) Add 4 to both sides: \[ 9f(2) = 6 \] Divide by 9: \[ f(2) = \frac{6}{9} = \frac{2}{3} \] ### Final Answer Thus, the value of \( f(2) \) is: \[ \boxed{\frac{2}{3}} \]
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