In a triangle ABC

A triangle has two sides y=m_1x and y=m_2x where m_1 and m_2 are the roots of the equation b alpha^2+2h alpha +a=0 . If (a,b) be the orthocenter of the triangle, then find the equation of the third side in terms of a , b and h .

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to

If H is the orthocentre of triangle ABC, R = circumradius and P = AH + BH + CH , then

In an acute angled triangle ABC , let AD, BE and CF be the perpendicular opposite sides of the triangle. The ratio of the product of the side lengths of the triangles DEF and ABC , is equal to

If R and R' are the circumradii of triangles ABC and OBC, where O is the orthocenter of triangle ABC, then :

If R and R' are the circumradii of triangles ABC and OBC, where O is the orthocenter of triangle ABC, then :

The orthocenter of the triangle formed by the lines xy=0 and x+y=1 is

Let H be the orthocentre of triangle ABC. Then angle subtended by side BC at the centre of incircle of Delta CHB is