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In a right angled triangle ABC, the bise...

In a right angled triangle ABC, the bisector of the right angle C divides AB into segment x and y and `tan((A-B)/(2))=t,` then x:y is equal to

A

`(1+t) : (1-t)`

B

`(1-t) : (t+1)`

C

`1: (1+t)`

D

`(1-t) :1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the right-angled triangle ABC with the right angle at C. The angle bisector of angle C divides the side AB into segments x and y. We are also given that \(\tan\left(\frac{A - B}{2}\right) = t\). We need to find the ratio \(x:y\). ### Step-by-Step Solution: 1. **Understanding the Triangle**: In triangle ABC, angle C is 90 degrees. Therefore, angles A and B are complementary, meaning \(A + B = 90^\circ\). 2. **Using the Angle Bisector Theorem**: The angle bisector of angle C divides the opposite side AB into segments x and y such that: \[ \frac{x}{y} = \frac{a}{b} \] where \(a\) is the length of side BC and \(b\) is the length of side AC. 3. **Relating Angles and Sides**: We can express \(a\) and \(b\) in terms of x and y. Let: \[ a = xk \quad \text{and} \quad b = yk \] for some constant \(k\). 4. **Using the Given Tangent Expression**: We know: \[ \tan\left(\frac{A - B}{2}\right) = t \] Using the identity for tangent of half-angle difference: \[ \tan\left(\frac{A - B}{2}\right) = \frac{\sin(A - B)}{1 + \cos(A - B)} \] This can also be expressed as: \[ t = \frac{a - b}{a + b} \cdot \cot\left(\frac{C}{2}\right) \] Since \(C = 90^\circ\), \(\cot\left(\frac{C}{2}\right) = \cot(45^\circ) = 1\). 5. **Substituting Values**: Substituting \(a\) and \(b\): \[ t = \frac{xk - yk}{xk + yk} = \frac{x - y}{x + y} \] We can cancel \(k\) since it is common in both numerator and denominator. 6. **Cross Multiplying**: Rearranging gives: \[ xt + yt = x - y \] Rearranging further: \[ xt - x = -y - yt \] Factoring out x and y: \[ x(t - 1) = -y(1 + t) \] 7. **Finding the Ratio**: Multiplying both sides by -1: \[ x(1 - t) = y(1 + t) \] Dividing both sides by y: \[ \frac{x}{y} = \frac{1 + t}{1 - t} \] Therefore, we can express the ratio \(x:y\) as: \[ x:y = 1 + t : 1 - t \] ### Final Answer: Thus, the ratio \(x:y\) is equal to \(1 + t : 1 - t\).
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    A
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    B
    3.6
    C
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    D
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