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Two sides of a rhombus OABC ( lying enti...

Two sides of a rhombus OABC ( lying entirely in first quadrant or fourth quadrant) of area equal to 2 sq. units, are `y =x/sqrt(3), y=sqrt(3)x` Then possible coordinates of B is/are (O being the origin).

A

`(1+sqrt(3),1sqrt(3))`

B

`(-1,-sqrt(3),-1sqrt(3))`

C

`(3+sqrt(3),3+sqrt(3))`

D

`(sqrt(3)-1,sqrt(3)-1)`

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