Home
Class 11
PHYSICS
A body of mass 100 kg falls on the earth...

A body of mass 100 kg falls on the earth from infinity. What will be its velocity on reaching the earth ? Radius of the earth is 6400 km and g = 9.8 `ms^(-2)` . Air friction is negligible.

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SELF ASSESSMENT PAPER 02

    ICSE|Exercise SECTION - C (Answer the following ) |8 Videos
  • SELF ASSESSMENT PAPER 02

    ICSE|Exercise SECTION-D (Answer the following )|6 Videos
  • SELF ASSESSMENT PAPER 02

    ICSE|Exercise SECTION - A(Answer the following ) |7 Videos
  • SELF ASSESSMENT PAPER 01

    ICSE|Exercise SECION- D (Answer the following ) |6 Videos
  • SELF ASSESSMENT PAPER 3

    ICSE|Exercise Section-D|6 Videos

Similar Questions

Explore conceptually related problems

A small body of mass m falls to the earth from infintie distance away. What will be its velocity or reaching the earth? (Radius of the earth = R, acceleration due to gravity on the surface of the earth is g) :-

A satellite circled around the earth at a distance of 100 km. Determine its orbital velocity, if the radius of the earth is 6400 km and g = 9.8 ms^(-2) .

An artifical satellite cicles round the earth at a distance of 3400 km. Calculate the orbital velocity. Given the radius of the earth is 6400km. G = 9.8 ms^(-2) .

Calculate the mass of the earth from the following data. Radius of the earth, 6371km, g = 9.8 ms^(-2)

A what height above the earth's surface the value of g becomes 25% of its value on the earth if radius of the earth is 6400km.

A body falls freely from a height 'h' its average velocity when it reaches earth is

An earth satellite makes a complete revolution around the earth in 120 minutes. If the orbit is circular calculate the height of satellite above the earth. Radius of the earth = 6400 km g = 9.8 ms^(-2) .

The mass of a body on the surface of the earth is 70kg. What will be its (i) mass and (ii) weight at an altitude of 100km? Radius of the earth is 6371km.

Find the value of G from the following data. Mass of the earth = 6 xx 10^(24) kg , radius of the earth = 6371km and g = 9.8 m//s

If 'g' on the surface of the earth is 9.8ms^(-2) , find its value at a depth of 3200 km (radius of the earth = 6400 km)