On heating chloroform with aqueous potash we get

Options

A. butanoic acid
B. propanoic acid
C. ethanoic acid
D. methanoic acid.

Explanation

To solve the problem of what we get when heating chloroform (CHCl3) with aqueous potash (KOH), we can break down the reaction step by step.

### Step 1: Identify the Reactants
- The reactants in this reaction are chloroform (CHCl3) and aqueous potash (KOH).

### Step 2: Understand the Reaction
- Chloroform contains three chlorine atoms that can be substituted by hydroxide ions (OH-) from KOH. The reaction involves the substitution of chlorine atoms in chloroform.

### Step 3: Reaction Mechanism
1. **First Step:**
- Chloroform reacts with KOH.
- The three chlorine atoms in chloroform are replaced by three hydroxide ions from KOH.
- This leads to the formation of potassium chloride (KCl) and formic acid (HCOOH).
- The reaction can be represented as:
\[ CHCl_3 + 3 KOH \rightarrow HCOOH + 3 KCl + 2 H_2O \]

2. **Second Step:**
- The formic acid (HCOOH) then reacts with the remaining KOH.
- This leads to the formation of potassium formate (HCOOK) and water (H2O).
- The reaction can be represented as:
\[ HCOOH + KOH \rightarrow HCOOK + H_2O \]

### Step 4: Final Products
- After both steps, the final products of the reaction are:
- Potassium formate (HCOOK)
- Potassium chloride (KCl)
- Water (H2O)

### Summary of the Reaction
- Overall, the complete reaction can be summarized as:
\[ CHCl_3 + 4 KOH \rightarrow HCOOK + 3 KCl + 2 H_2O \]

### Final Answer
On heating chloroform with aqueous potash, we get potassium formate (HCOOK), potassium chloride (KCl), and water (H2O).

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