The total number of electrons that take part in forming bonds in `N_2` is

Options

A. 2
B. 4
C. 6
D. 10

Explanation

To determine the total number of electrons that take part in forming bonds in the nitrogen molecule (N₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Structure of Nitrogen:**
- Each nitrogen atom (N) has an atomic number of 7. Therefore, the electronic configuration of nitrogen is:
- \(1s^2 2s^2 2p^3\)
- This means each nitrogen atom has 5 valence electrons (2 from the 2s subshell and 3 from the 2p subshell).

2. **Calculate the Total Valence Electrons in N₂:**
- Since N₂ is a diatomic molecule, it consists of two nitrogen atoms.
- Total valence electrons in N₂ = \(5 \text{ (from one N)} + 5 \text{ (from the other N)} = 10\) valence electrons.

3. **Determine the Bonding Electrons:**
- In N₂, the two nitrogen atoms form a triple bond. A triple bond consists of:
- 1 sigma bond and 2 pi bonds.
- Each bond (whether sigma or pi) involves 2 electrons. Therefore, for a triple bond:
- Total bonding electrons = \(3 \text{ bonds} \times 2 \text{ electrons/bond} = 6 \text{ electrons}\).

4. **Conclusion:**
- The total number of electrons that take part in forming bonds in N₂ is **6 electrons**.

### Final Answer:
The total number of electrons that take part in forming bonds in N₂ is **6**.

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