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Find the angle between the vector vec(a)...

Find the angle between the vector `vec(a) =2 hat(i) + 3hat(j) - 4 hat(k) and vec(b) = 4hat(i) +5 hat(j) - 2hat(k)` .

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To find the angle between the vectors \(\vec{a} = 2 \hat{i} + 3 \hat{j} - 4 \hat{k}\) and \(\vec{b} = 4 \hat{i} + 5 \hat{j} - 2 \hat{k}\), we can use the dot product formula. Here are the steps to solve the problem: ### Step 1: Calculate the Dot Product of Vectors \(\vec{a}\) and \(\vec{b}\) The dot product of two vectors \(\vec{a}\) and \(\vec{b}\) is given by: \[ \vec{a} \cdot \vec{b} = a_x b_x + a_y b_y + a_z b_z ...
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Find the angle between vec(A) = hat(i) + 2hat(j) - hat(k) and vec(B) = - hat(i) + hat(j) - 2hat(k)

Find the angle between the vectors 2 hat(i) - hat(j) - hat(k) and 3 hat(i) + 4 hat(j) - hat(k) .

Knowledge Check

  • Unit vectors perpendicular to the plane of vectors vec(a) = 2 hat(*i) - 6 hat(j) - 3 hat(k) and vec(b) = 4 hat(i) + 3 hat(j) - hat(k) are

    A
    `+- ( 4 hat(i) + 3 hat(j) - hat(k))/(sqrt(26))`
    B
    `+- ( 2 hat(i) - 6 hat(j) - 3 hat(k))/( 7)`
    C
    `+- ( 2 hat(i) - 3 hat(j) +6 hat(k))/( 7)`
    D
    `+- ( 3 hat(i) -2 hat(j) + 6 hat(k))/(7)`
  • The number of unit vectors perpendicular to the vector vec(a) = 2 hat(i) + hat(j) + 2 hat(k) and vec(b) = hat(j) + hat(k) is

    A
    one
    B
    two
    C
    three
    D
    infinite
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