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An eletric bulb of volume 250 cm^3 was s...

An eletric bulb of volume `250 cm^3` was sealed off during manufacture at a pressure of `10^3 mm` of mercury at `27^@ C`. Compute the number of air molecules contained in the bulb. Given that `R = 8.31 J//mol - K and N_A= 6.01 xx 10^23 per mol`.

Text Solution

Verified by Experts

The correct Answer is:
`8 xx 10^(15)`
`V_(2) = P_(1) V_(1) T_(2) //T_(1) P_(2) = 10^(-4) xx 250 xx 273 // 300 xx 76 = 2.99 xx 10^(-4) cm^(3)`
Number of particles in the bulb `= V_(2) N // 22400 = 2.99 xx 10^(-4) xx 6 xx 10^(23)//22400 = 8 xx 10^(15)`
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