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An eletric bulb of volume 250 cm^3 was s...

An eletric bulb of volume `250 cm^3` was sealed off during manufacture at a pressure of `10^3 mm` of mercury at `27^@ C`. Compute the number of air molecules contained in the bulb. Given that `R = 8.31 J//mol - K and N_A= 6.01 xx 10^23 per mol`.

Text Solution

Verified by Experts

The correct Answer is:
`8 xx 10^(15)`
`V_(2) = P_(1) V_(1) T_(2) //T_(1) P_(2) = 10^(-4) xx 250 xx 273 // 300 xx 76 = 2.99 xx 10^(-4) cm^(3)`
Number of particles in the bulb `= V_(2) N // 22400 = 2.99 xx 10^(-4) xx 6 xx 10^(23)//22400 = 8 xx 10^(15)`
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An electric bulb of volume 250 cc was sealed during manufacturing at a pressure of 10^(-3)mm of mercury at 27^(@)C . Compute the number of air molecules contained in the bulb. Avogadro constant =6xx10^(23)mol^(-1), density of mercury =13600kgm^(-3) and g=10ms^(-2) .

An electric bulb of volume 250cc was sealed during manufacturing at a pressure of 10^(-3) mm of mercury at 27^(@) C. Compute the number of air molecules contained in the bulb.Avogadro constant =6xx10^(23)mol^(-1), density of mercury =13600kgm^(-3)and g=10ms^(-2) .

Knowledge Check

  • One half mole each of nitrogen, oxygen and carbon dioxide are mixed in enclosure of volume 5 litres and temperature 27^(@) C . Calculate the pressure exerted by the mixture. Given R = 8.31 J mol^(-1) K^(-1) .

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    B
    `5xx10^(5)Nm^(2)`
    C
    `6xx10^(5)Nm^(2)`
    D
    `3xx10^(5)Nm^(-2)`

  • A gas at 300 K has pressure 4 xx 10^(-10) N//m^(2) . IF k = 1.38 xx 10^(-23) J//K , the number of "molecule"// cm^(3) is of the order of

    A
    `10^(3)`
    B
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    C
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