The gravitational force between two stones of mass 1 kg each separted by a distance of 1 metre in vaccum is

Options

A. zero
B. `6.675 xx 10^(-5)` newton
C. `6.675 xx 10^(-11)` newton
D. `6.75 xx 10^(-8)` newton

Explanation

To find the gravitational force between two stones of mass 1 kg each, separated by a distance of 1 meter in vacuum, we can use Newton's law of universal gravitation. The formula for gravitational force (F) is given by:

\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]

Where:
- \( F \) is the gravitational force,
- \( G \) is the universal gravitational constant, approximately \( 6.675 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \),
- \( m_1 \) and \( m_2 \) are the masses of the two objects,
- \( r \) is the distance between the centers of the two masses.

### Step-by-Step Solution:

1. **Identify the Masses and Distance**:
- Both stones have a mass \( m_1 = 1 \, \text{kg} \) and \( m_2 = 1 \, \text{kg} \).
- The distance \( r \) between them is \( 1 \, \text{m} \).

2. **Substitute the Values into the Formula**:
- We substitute \( G = 6.675 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \), \( m_1 = 1 \, \text{kg} \), \( m_2 = 1 \, \text{kg} \), and \( r = 1 \, \text{m} \) into the gravitational force formula:
\[ F = \frac{6.675 \times 10^{-11} \cdot 1 \cdot 1}{1^2} \]

3. **Calculate the Denominator**:
- Since \( r^2 = 1^2 = 1 \), the equation simplifies to:
\[ F = 6.675 \times 10^{-11} \, \text{N} \]

4. **Final Result**:
- Therefore, the gravitational force between the two stones is:
\[ F = 6.675 \times 10^{-11} \, \text{N} \]

### Conclusion:
The gravitational force between the two stones is \( 6.675 \times 10^{-11} \, \text{N} \).