Calculate the mass of pure `CO_(2)` formed when 500 g of magnesium carbonate of 64 % purity dissolves in an excess of HCl as given below :
`MgCO_(3) + 2HCl to MgCl_(2) + H_(2)O + CO_(2)`
(Mg = 24, C = 12, O = 16, H = 1, Cl = 35.5)

Explanation

To solve the problem, we need to calculate the mass of pure CO₂ formed when 500 g of magnesium carbonate (MgCO₃) with 64% purity reacts with excess hydrochloric acid (HCl).

### Step-by-Step Solution:

1. **Calculate the mass of pure magnesium carbonate (MgCO₃)**:
- Given that the purity of magnesium carbonate is 64%, we can find the mass of pure magnesium carbonate in the 500 g sample.
\[
\text{Mass of pure MgCO}_3 = \text{Purity} \times \text{Total mass} = \frac{64}{100} \times 500 \, \text{g} = 320 \, \text{g}
...