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Let alpha , beta be the roots of x^2-x+p...

Let `alpha` , `beta` be the roots of `x^2-x+p=0 and gamma,delta` be the roots of `x^2-4x+q=0 `. If `alpha,beta,gamma` are in GP , then the integer values of p and q respectively are:

A

-2,-32

B

-2,3

C

-6,3

D

-6,-32

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If alpha,beta are the roots of x^2-px+1=0 and gamma is a root of x^2+px+1=0 , then (alpha+gamma)(beta+gamma) is

    A
    0
    B
    1
    C
    -1
    D
    p

  • If alpha,beta are the roots x^(2)-px+1=0 and gamma "is a root of "x^(2)+px+1=0 ,then (alpha+gamma)(beta+gamma) is -

    A
    0 (zero)
    B
    1
    C
    `-1`
    D
    p

  • If alpha,beta are the roots of x^2+px+q =0 and also of x^(2n)+p^n x^n+q^n=0 and if alpha/beta,beta/alpha are root of x^n+1+(x+1)^n =0, then n is

    A
    an integer
    B
    an odd integer
    C
    an even integer
    D
    none of the above

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