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If X = {4^n-3n-1: n in N} and Y = {9(n-1...

If X = {`4^n-3n-1: n in N}` and Y = {`9(n-1):n in N`} where N is the set of natural numbers then `X cup Y` is equal to

A

X

B

Y

C

N

D

Y-X

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • If aN={ax:x in N(natural number)} then 3N cap 7N is equal to

    A
    21N
    B
    10N
    C
    4N
    D
    14N

  • If n is a natural number, then (4^(n) -3n -1) is always divisible by-

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    9
    B
    18
    C
    27
    D
    21

  • If n is a natural number then (12 ^(n) + 25 ^(n-1)) is divisible by-

    A
    9
    B
    13
    C
    12
    D
    21

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