The correct order of I.`E_(2)`. Is:

Options

A. NegtFgtOgtN
B. OgtFgtNegtN
C. NegtOgtFgtN
D. OgtNegtFgtN

Explanation

To determine the correct order of the second ionization energy (I.E.₂) for the elements Neon (Ne), Fluorine (F), Oxygen (O), and Nitrogen (N), we can follow these steps:

### Step 1: Write the Electronic Configurations
First, we need to write the electronic configurations for the elements in question:

- **Neon (Ne)**: 1s² 2s² 2p⁶
- **Fluorine (F)**: 1s² 2s² 2p⁵
- **Oxygen (O)**: 1s² 2s² 2p⁴
- **Nitrogen (N)**: 1s² 2s² 2p³

### Step 2: Determine the Configuration After First Ionization
Next, we will determine the electronic configurations after the removal of one electron (first ionization):

- **Neon (Ne)**: 1s² 2s² 2p⁶ → 1s² 2s² 2p⁵
- **Fluorine (F)**: 1s² 2s² 2p⁵ → 1s² 2s² 2p⁴
- **Oxygen (O)**: 1s² 2s² 2p⁴ → 1s² 2s² 2p³
- **Nitrogen (N)**: 1s² 2s² 2p³ → 1s² 2s² 2p²

### Step 3: Analyze the Size and Effective Nuclear Charge
Now, we analyze the trend in atomic size and effective nuclear charge as we move across the period from left to right:

- As we move from Nitrogen to Neon, the atomic size decreases due to an increase in effective nuclear charge. This means that the attraction between the nucleus and the electrons increases.

### Step 4: Relate Size to Ionization Energy
The ionization energy is the energy required to remove an electron from an atom. The smaller the size of the atom (or ion), the higher the ionization energy required to remove an electron:

- **Neon** has the smallest size and therefore has the highest ionization energy.
- **Oxygen** has a half-filled configuration after the first ionization, which is more stable, leading to a higher second ionization energy compared to **Fluorine**.
- **Nitrogen** has a larger size than both Oxygen and Fluorine, resulting in a lower ionization energy.

### Step 5: Order the Second Ionization Energies
Based on the analysis, we can order the second ionization energies as follows:

1. **Neon (Ne)** - Highest I.E.₂
2. **Oxygen (O)**
3. **Fluorine (F)**
4. **Nitrogen (N)** - Lowest I.E.₂

### Final Answer
The correct order of I.E.₂ is: **Ne > O > F > N**.