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The correct order of Cl-O bond order is ...

The correct order of Cl-O bond order is :

A

`ClO_(3)^(-) lt ClO_(4)^(-) lt ClO_(2)^(-) lt ClO^(-)`

B

`ClO^(-) lt ClO_(4)^(-) lt ClO_(3)^(-) lt ClO_(2)^(-)`

C

`ClO^(-) lt ClO_(2)^(-) lt ClO_(3)^(-) lt ClO_(4)^(-)`

D

`ClO_(4)^(-) lt ClO_(3)^(-) lt ClO_(3)^(-) lt ClO^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the bond order of Cl-O in different chlorine oxoanions, we can use the following formula: **Bond Order = (Valency of Peripheral Atom + Charge on the Radical) / Total Number of Peripheral Atoms** Let's calculate the bond order for each of the chlorine oxoanions step by step: ### Step 1: Calculate Bond Order for ClO3⁻ 1. **Identify the Peripheral Atom**: The peripheral atom is oxygen (O). 2. **Valency of Oxygen**: The valency of oxygen is 2. 3. **Charge on the Radical**: The charge on ClO3⁻ is -1. 4. **Total Number of Peripheral Atoms**: There are 3 oxygen atoms. **Bond Order Calculation**: \[ \text{Bond Order} = \frac{(2 + (-1))}{3} = \frac{1}{3} = \frac{5}{3} \approx 1.67 \] ### Step 2: Calculate Bond Order for ClO4⁻ 1. **Identify the Peripheral Atom**: The peripheral atom is oxygen (O). 2. **Valency of Oxygen**: The valency of oxygen is 2. 3. **Charge on the Radical**: The charge on ClO4⁻ is -1. 4. **Total Number of Peripheral Atoms**: There are 4 oxygen atoms. **Bond Order Calculation**: \[ \text{Bond Order} = \frac{(2 + (-1))}{4} = \frac{1}{4} = \frac{7}{4} \approx 1.75 \] ### Step 3: Calculate Bond Order for ClO2⁻ 1. **Identify the Peripheral Atom**: The peripheral atom is oxygen (O). 2. **Valency of Oxygen**: The valency of oxygen is 2. 3. **Charge on the Radical**: The charge on ClO2⁻ is -1. 4. **Total Number of Peripheral Atoms**: There are 2 oxygen atoms. **Bond Order Calculation**: \[ \text{Bond Order} = \frac{(2 + (-1))}{2} = \frac{1}{2} = 1.5 \] ### Step 4: Calculate Bond Order for ClO⁻ 1. **Identify the Peripheral Atom**: The peripheral atom is oxygen (O). 2. **Valency of Oxygen**: The valency of oxygen is 2. 3. **Charge on the Radical**: The charge on ClO⁻ is -1. 4. **Total Number of Peripheral Atoms**: There is 1 oxygen atom. **Bond Order Calculation**: \[ \text{Bond Order} = \frac{(2 + (-1))}{1} = \frac{1}{1} = 1 \] ### Summary of Bond Orders: - ClO4⁻: Bond Order ≈ 1.75 - ClO3⁻: Bond Order ≈ 1.67 - ClO2⁻: Bond Order = 1.5 - ClO⁻: Bond Order = 1 ### Final Order of Bond Orders: The correct order of Cl-O bond order from highest to lowest is: 1. ClO4⁻ (≈ 1.75) 2. ClO3⁻ (≈ 1.67) 3. ClO2⁻ (1.5) 4. ClO⁻ (1) Thus, the correct answer is option 3. ---
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