Assuming pure 2s and 2p orbitals of carbon are used in forming `CH_(4)` molecule, which of the following statement is false ?

Options

A. Three C-H bonds will be at right angle
B. One C-H bond will be weaker than other three C-H bonds
C. The shape of molecule will be tetrahedral
D. The angle of C-H bond formed by s-s overlapping will be uncertain with respect to other three bonds.

Explanation

To determine which statement is false regarding the formation of the `CH4` molecule using pure 2s and 2p orbitals of carbon, we can analyze the bonding process step by step.

### Step-by-Step Solution:

1. **Understanding Carbon's Electron Configuration**:
- Carbon has an atomic number of 6, leading to an electron configuration of `1s² 2s² 2p²`. The outermost electrons are in the 2s and 2p orbitals.

2. **Excitation of Electrons**:
- In order to form bonds, one of the 2s electrons can be excited to the 2p orbital, resulting in the excited state configuration: `1s² 2s¹ 2p³`. This means there is one electron in the 2s orbital and three in the 2p orbitals.

3. **Orbital Shapes and Orientation**:
- The 2s orbital is spherical, while the 2p orbitals (px, py, pz) are dumbbell-shaped and oriented along the x, y, and z axes respectively.

4. **Bond Formation with Hydrogen**:
- When carbon bonds with four hydrogen atoms, the bonding involves overlaps between the carbon orbitals and the hydrogen 1s orbitals.
- The overlap occurs as follows:
- One hydrogen atom overlaps with the 2s orbital (s-s overlap).
- The other three hydrogen atoms overlap with the three 2p orbitals (p-s overlap).

5. **Analyzing the Bond Angles**:
- The three bonds formed by the 2p orbitals (p-s overlaps) will be at right angles to each other, corresponding to the orientation of the p orbitals.
- However, the bond formed by the 2s orbital does not have a defined angle with respect to the other three bonds, as it does not participate in hybridization.

6. **Evaluating the Statements**:
- **Statement 1**: "The three CH bonds will be at right angles." (True)
- **Statement 2**: "One CH bond will be weaker than the other three CH bonds." (True)
- **Statement 3**: "The shape of the molecule is going to be tetrahedral." (False)
- **Statement 4**: "The angle of the carbon-hydrogen bond formed by the S-S overlapping will be uncertain with respect to the other three bonds." (True)

7. **Conclusion**:
- The false statement is **Statement 3**, as the shape of the molecule will not be tetrahedral when using pure 2s and 2p orbitals without hybridization.

### Final Answer:
The false statement is: **The shape of the molecule is going to be tetrahedral.**

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