Home
Class 12
CHEMISTRY
If the central atom is of third row or b...

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly `90^(@)`, if the substituent's electronegativity value is `le 2.5`.
The hybridisation of atomic orbitals of central atom "Xe" in `XeO_(4), XeO_(2)F_(2) and XeOF_(4)` respectively.

A

`sp^(3),sp^(3)d^(2),sp^(3)d^(2)`

B

`sp^(3)d,sp^(3)d,sp^(3)d^(2)`

C

`sp^(3),sp^(3)d^(2),sp^(3)d`

D

`sp^(3),sp^(3)d,sp^(3)d^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the hybridization of the central atom xenon (Xe) in the compounds XeO4, XeO2F2, and XeOF4, we will follow these steps: ### Step 1: Determine the Valence Electrons of Xenon Xenon is in Group 18 of the periodic table and has 8 valence electrons. ### Step 2: Analyze the Compounds 1. **XeO4**: - Each oxygen (O) atom forms 2 bonds (1 sigma and 1 pi). - There are 4 oxygen atoms, contributing to 4 bonding pairs. - Since there are no lone pairs on xenon in this compound, the total number of electron pairs is 4 (bonding pairs). - **Hybridization**: The hybridization is sp³ (4 electron pairs). 2. **XeO2F2**: - Each oxygen atom forms 2 bonds (1 sigma and 1 pi), contributing 2 bonding pairs. - Each fluorine (F) atom forms 1 bond, contributing 2 more bonding pairs. - This gives a total of 4 bonding pairs. - Xenon has 1 lone pair remaining after forming these bonds. - **Total Electron Pairs**: 4 bonding pairs + 1 lone pair = 5. - **Hybridization**: The hybridization is sp³d. 3. **XeOF4**: - Each oxygen atom forms 2 bonds (1 sigma and 1 pi), contributing 2 bonding pairs. - Each fluorine atom forms 1 bond, contributing 4 more bonding pairs. - This gives a total of 4 bonding pairs from the fluorine and 1 from oxygen. - There is 1 lone pair remaining on xenon. - **Total Electron Pairs**: 4 bonding pairs + 1 lone pair = 5. - **Hybridization**: The hybridization is sp³d². ### Summary of Hybridization - **XeO4**: sp³ - **XeO2F2**: sp³d - **XeOF4**: sp³d² ### Final Answer - The hybridization of Xe in XeO4 is sp³. - The hybridization of Xe in XeO2F2 is sp³d. - The hybridization of Xe in XeOF4 is sp³d².
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise Level 3 (Passive 4)|5 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise Level 3 (Passive 5)|6 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise Level 3 (Passive 2)|6 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|64 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise LEVEL 2|144 Videos