Hybridisation involves the mixing of orbitals having comparable energhies of same atom. Hybridised orbitals perform efficient overlapping than overlapping by pure s, p or orbitals.
Which of the following is not correctly match between given species and type of overlapping ?

Options

A. `XeO_(3)` : Three `(d pi - p pi)` bonds
B. `H_(2)SO_(4)` : Two `(d pi - p pi)` bonds
C. `SO_(3)` : Three `(d pi - p pi)` bonds
D. `HClO_(4)` : Three `(d pi - p pi)` bonds

Explanation

To solve the question regarding the incorrect matching of species with their type of overlapping, we will analyze each option step-by-step.

### Step 1: Understand the concept of hybridization and overlapping
Hybridization involves the mixing of atomic orbitals of comparable energies to form new hybrid orbitals. These hybrid orbitals can overlap more effectively than the original atomic orbitals, leading to stronger bonds.

### Step 2: Analyze each option
We have four options to analyze for their correctness regarding the type of overlapping.

#### Option 1: XeO3 - dπ-pπ bond
- **Analysis**: Xenon (Xe) has the electronic configuration of [Kr] 4d10 5s2 5p6. In XeO3, Xe forms three sigma bonds and three pi bonds with oxygen. The pi bonds involve d orbitals of xenon overlapping with p orbitals of oxygen. This is a correct match.

#### Option 2: H2SO4 - dπ-pπ bond
- **Analysis**: Sulfur (S) has the electronic configuration of [Ne] 3s2 3p4. In H2SO4, sulfur forms four sigma bonds and two pi bonds. The pi bonds are formed by the overlap of d orbitals of sulfur with p orbitals of oxygen. This is also a correct match.

#### Option 3: SO3 - dπ-pπ bond
- **Analysis**: In SO3, sulfur forms three sigma bonds and two pi bonds. The pi bonds consist of one pπ-pπ bond and two dπ-pπ bonds. The statement claims that SO3 has three dπ-pπ bonds, which is incorrect because only two of the pi bonds involve d orbitals. Thus, this is the incorrect match.

#### Option 4: HClO4 - dπ-pπ bond
- **Analysis**: Chlorine (Cl) has the electronic configuration of [Ne] 3s2 3p5. In HClO4, chlorine forms four sigma bonds and three pi bonds, with the pi bonds formed by the overlap of d orbitals of chlorine with p orbitals of oxygen. This is a correct match.

### Conclusion
Based on the analysis, the incorrect match is found in **Option 3: SO3 - dπ-pπ bond**. The correct type of overlapping for SO3 involves one pπ-pπ bond and two dπ-pπ bonds.

### Final Answer
**The incorrect match is Option 3: SO3 - dπ-pπ bond.**

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