Unmatched characteristic of complex `[PdCl_(2)(H_(2)O)_(2)(NH_(3))_(2)]^(2+)` is:

Options

A. Diamagnetic
B. Low spin
C. Geometrical isomerism
D. Fac. And Mer. Form

Explanation

To determine the unmatched characteristic of the complex \([PdCl_2(H_2O)_2(NH_3)_2]^{2+}\), we will follow these steps:

### Step 1: Determine the Oxidation State of Palladium
Let the oxidation state of Palladium (Pd) be \(X\). The ligands in the complex are:
- Chloride (Cl) is a negative ligand with a charge of -1, and there are 2 of them: \(2 \times (-1) = -2\).
- Water (H2O) is a neutral ligand with a charge of 0, and there are 2 of them: \(2 \times 0 = 0\).
- Ammonia (NH3) is also a neutral ligand with a charge of 0, and there are 2 of them: \(2 \times 0 = 0\).

The overall charge of the complex is +2. Therefore, we can set up the equation:
\[ X - 2 + 0 + 0 = +2 \]
Solving for \(X\):
\[ X - 2 = 2 \implies X = 4 \]
Thus, the oxidation state of Palladium is +4.

### Step 2: Determine the Electronic Configuration of Palladium
The electronic configuration of Palladium (Pd) in its elemental state is:
\[ [Xe] 4d^{10} 5s^0 \]
When Palladium is in the +4 oxidation state, it loses 4 electrons. The configuration becomes:
\[ 4d^6 \]
This indicates that 4 electrons have been removed from the 4d and 5s orbitals.

### Step 3: Determine the Hybridization of the Complex
In the case of Palladium(IV), the hybridization can be determined by the number of ligands attached. The complex has 6 ligands (2 Cl, 2 H2O, and 2 NH3). The hybridization can be deduced as follows:
- The hybridization for a coordination number of 6 is typically \(d^2sp^3\), which corresponds to an octahedral geometry.

### Step 4: Analyze the Magnetic Properties
Since all the 4d electrons are paired in the octahedral field, the complex is diamagnetic. This means it has no unpaired electrons.

### Step 5: Check for Isomerism
The complex can exhibit geometrical isomerism due to the presence of two different types of ligands (Cl and NH3). The possible isomers include:
- **Cis isomer**: where similar ligands are adjacent.
- **Trans isomer**: where similar ligands are opposite each other.

However, the complex cannot exhibit facial and meridional isomerism because it does not have the required arrangement of ligands (it is not of the form MA3B3).

### Conclusion
The unmatched characteristic of the complex \([PdCl_2(H_2O)_2(NH_3)_2]^{2+}\) is that it does not exhibit facial and meridional isomerism.