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In which case racemic mixture is obtaine...

In which case racemic mixture is obtained on mixing its mirror images (d & l form) is 1:1 molar ratio:

A

trans-`[Co(gly)_(3)]`

B

`[Ni(DMG)_(2)]`

C

cis-`[Cu(gly)_(2)]`

D

`[Zn(en)(gly)]^(+)`

Text Solution

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The correct Answer is:
To solve the question regarding the formation of a racemic mixture by mixing mirror images (D and L forms) in a 1:1 molar ratio, we need to follow a systematic approach: ### Step-by-Step Solution: 1. **Understanding Racemic Mixture**: - A racemic mixture is formed when two enantiomers (optically active compounds that are mirror images of each other) are mixed in equal amounts (1:1 ratio). This results in a mixture that is optically inactive because the optical activities of the two enantiomers cancel each other out. 2. **Identifying Optically Active Compounds**: - For a compound to be optically active, it must lack a plane of symmetry. Therefore, we need to analyze the given options to determine which compounds are optically active. 3. **Analyzing the Options**: - **Option A: trans-CO-glycinate whole thrice**: - This compound has a bidentate ligand (glycinate) that is unsymmetrical. The structure does not have a plane of symmetry, making it optically active. Thus, mixing its D and L forms will yield a racemic mixture. - **Option B: Nickel DMG whole twice**: - Nickel with dimethylglyoxime (DMG) forms a square planar complex. This structure has a plane of symmetry, making it optically inactive. Therefore, it cannot form a racemic mixture. - **Option C: cis-Cu-glycinate whole twice**: - This compound also forms a square planar structure with glycinate. Similar to option B, it has a plane of symmetry, making it optically inactive and unable to form a racemic mixture. - **Option D: Zinc-EN-glycinate whole plus**: - Zinc with ethylenediamine (EN) and glycinate forms a tetrahedral structure. However, the presence of a plane of symmetry in this structure renders it optically inactive, thus it cannot form a racemic mixture. 4. **Conclusion**: - After analyzing all options, the only compound that can form a racemic mixture when its D and L forms are mixed in a 1:1 ratio is **Option A: trans-CO-glycinate whole thrice**. ### Final Answer: The correct option is **A: trans-CO-glycinate whole thrice**. ---
To solve the question regarding the formation of a racemic mixture by mixing mirror images (D and L forms) in a 1:1 molar ratio, we need to follow a systematic approach: ### Step-by-Step Solution: 1. **Understanding Racemic Mixture**: - A racemic mixture is formed when two enantiomers (optically active compounds that are mirror images of each other) are mixed in equal amounts (1:1 ratio). This results in a mixture that is optically inactive because the optical activities of the two enantiomers cancel each other out. 2. **Identifying Optically Active Compounds**: ...
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