`Pb(NO_(3))_(2)+2NaOH to Pb(OH)_(2)darr+2NaNO_(3)`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To analyze the reaction \( \text{Pb(NO}_3\text{)}_2 + 2\text{NaOH} \rightarrow \text{Pb(OH)}_2 \downarrow + 2\text{NaNO}_3 \), we will follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are lead(II) nitrate, \( \text{Pb(NO}_3\text{)}_2 \), and sodium hydroxide, \( \text{NaOH} \).

### Step 2: Write the Products
The products formed in this reaction are lead(II) hydroxide, \( \text{Pb(OH)}_2 \), and sodium nitrate, \( \text{NaNO}_3 \).

### Step 3: Determine the State of the Products
In this reaction, \( \text{Pb(OH)}_2 \) is indicated by a downward arrow (↓), which signifies that it is a precipitate. Sodium nitrate, \( \text{NaNO}_3 \), remains in solution.

### Step 4: Analyze the Reaction Type
This reaction is a double displacement (or double replacement) reaction where the cations and anions exchange partners.

### Step 5: Conclusion
Since \( \text{Pb(OH)}_2 \) is formed as a precipitate, we conclude that this reaction results in the formation of a precipitate.

### Final Answer
The reaction results in the **formation of a precipitate**.

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