`NaNO_(3) overset(Delta) to NaNO_(2)+O_(2)`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To analyze the reaction \( \text{NaNO}_3 \overset{\Delta}{\rightarrow} \text{NaNO}_2 + \text{O}_2 \) and determine its type, we can follow these steps:

### Step 1: Identify the Reactants and Products
The reactant is sodium nitrate (\( \text{NaNO}_3 \)) and the products are sodium nitrite (\( \text{NaNO}_2 \)) and oxygen gas (\( \text{O}_2 \)).

### Step 2: Determine the Oxidation States
Next, we need to calculate the oxidation states of the elements in the reactants and products.

1. **For \( \text{NaNO}_3 \)**:
- Sodium (Na) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
- Let the oxidation state of nitrogen (N) be \( x \).
- The equation for the oxidation state is:
\[ 1 + 3(-2) + x = 0 \implies 1 - 6 + x = 0 \implies x = +5 \]
- Therefore, in \( \text{NaNO}_3 \), Na is +1, N is +5, and O is -2.

2. **For \( \text{NaNO}_2 \)**:
- Sodium (Na) is +1.
- Oxygen (O) is -2.
- Let the oxidation state of nitrogen (N) be \( y \).
- The equation for the oxidation state is:
\[ 1 + 2(-2) + y = 0 \implies 1 - 4 + y = 0 \implies y = +3 \]
- Therefore, in \( \text{NaNO}_2 \), Na is +1, N is +3, and O is -2.

3. **For \( \text{O}_2 \)**:
- Oxygen in its elemental form has an oxidation state of 0.

### Step 3: Analyze the Changes in Oxidation States
- **Nitrogen** changes from +5 in \( \text{NaNO}_3 \) to +3 in \( \text{NaNO}_2 \) (reduction).
- **Oxygen** changes from -2 in \( \text{NaNO}_3 \) to 0 in \( \text{O}_2 \) (oxidation).

### Step 4: Identify the Type of Reaction
Since we have both oxidation (loss of electrons) and reduction (gain of electrons), this reaction is classified as a **redox reaction**.

### Step 5: Determine if it is a Decomposition Reaction
The reaction involves the breakdown of sodium nitrate into sodium nitrite and oxygen gas, indicating that it is a **decomposition reaction**.

### Conclusion
Thus, the reaction \( \text{NaNO}_3 \overset{\Delta}{\rightarrow} \text{NaNO}_2 + \text{O}_2 \) is a **thermal decomposition redox reaction**.