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H(3)PO(3)overset(Delta)toH(3)PO(4)+PH(3)...

`H_(3)PO_(3)overset(Delta)toH_(3)PO_(4)+PH_(3)uarr`

A

For disproportionation reaction.

B

For comproportionation reaction.

C

For either intermolecular redox reaction or displacement reaction

D

For either thermal combination redox reaction or thermal decomposition redox reaction.

Text Solution

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To solve the question regarding the reaction of phosphorous acid (H₃PO₃) decomposing into phosphoric acid (H₃PO₄) and phosphine (PH₃), we will analyze the oxidation states of phosphorus in each compound and determine the type of reaction taking place. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: The reaction given is: \[ \text{H}_3\text{PO}_3 \xrightarrow{\Delta} \text{H}_3\text{PO}_4 + \text{PH}_3 \] Here, H₃PO₃ is the reactant, and H₃PO₄ and PH₃ are the products. 2. **Determine the Oxidation States**: - For H₃PO₃: \[ \text{Let the oxidation state of P be } x. \] The equation for the oxidation state is: \[ 3(1) + x + 3(-2) = 0 \implies 3 + x - 6 = 0 \implies x = +3 \] - For H₃PO₄: \[ \text{Let the oxidation state of P be } y. \] The equation for the oxidation state is: \[ 3(1) + y + 4(-2) = 0 \implies 3 + y - 8 = 0 \implies y = +5 \] - For PH₃: \[ \text{Let the oxidation state of P be } z. \] The equation for the oxidation state is: \[ 3(-1) + z = 0 \implies -3 + z = 0 \implies z = -3 \] 3. **Analyze the Changes in Oxidation States**: - In H₃PO₃, phosphorus is in the +3 oxidation state. - In H₃PO₄, phosphorus is in the +5 oxidation state (oxidation). - In PH₃, phosphorus is in the -3 oxidation state (reduction). 4. **Identify the Type of Reaction**: - Since phosphorus in H₃PO₃ is both oxidized (to +5 in H₃PO₄) and reduced (to -3 in PH₃), this is a **disproportionation reaction**. - A disproportionation reaction is characterized by a single species undergoing both oxidation and reduction. 5. **Conclusion**: The reaction is a **disproportionation reaction** and can also be classified as a **thermal decomposition reaction** because it involves the breakdown of a single reactant into two products upon heating.
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Balance the following equations. (i) H_(3)PO_(3) to H_(3)PO_(4) + PH_(3) (ii) Ca + H_(2)O to Ca(OH)_(2) + H_(2) (iii) Fe_(2)(SO_(4))_(3) + NH_(3) +H_(2)O to Fe(OH)_(3) + (NH_(4))_(2)SO_(4)

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Knowledge Check

  • Phosphorous acid on heating gives the following products: 4H_(3)PO_(3)overset(Delta)rarr3H_(3)PO_(4)+PH_(3) The above reaction is an example of

    A
    oxidation
    B
    thermal decomposition
    C
    disproportionation
    D
    reduction
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