`NiCl_(2)("solution")+NaNO_(3)("solution") to `No reaction

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To analyze the reaction between NiCl₂ (solution) and NaNO₃ (solution) and determine why no reaction occurs, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are Nickel(II) chloride (NiCl₂) and Sodium nitrate (NaNO₃).

2. **Check for Possible Reactions**:
When mixing these two solutions, we need to consider if any double displacement (metathesis) reactions could occur. In a typical double displacement reaction, the cations and anions exchange partners.

3. **Write the Possible Products**:
The potential products from this reaction would be Nickel(II) nitrate (Ni(NO₃)₂) and Sodium chloride (NaCl).

4. **Solubility of the Products**:
- Ni(NO₃)₂ is soluble in water.
- NaCl is also soluble in water.
Since both potential products are soluble, no precipitate will form.

5. **Conclusion on Reaction**:
Since no precipitate forms and both products remain in solution, we conclude that there is no observable reaction between NiCl₂ and NaNO₃ in aqueous solutions.

6. **Determine the Color of the Solution**:
- NiCl₂ is a colored compound due to the presence of nickel ions, which have unpaired electrons that allow for d-d transitions, resulting in color.
- NaNO₃ is colorless because it contains sodium ions, which do not impart color.

7. **Final Answer**:
Since the solution remains colored due to NiCl₂ and no precipitate forms, the correct option is for a colored solution.