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The dipole moment of H(2)O(2) is more th...

The dipole moment of `H_(2)O_(2)` is more than that of `H_(2)O` but `H_(2)O_(2)` is not a good solvent because `:`

A

It has a very high dielectric constant so that ionic compounds cannot be dissolved in it

B

It does not act as an oxidising agent

C

It acts as a reducing agent

D

It dissociates easily and acts as an oxidising agent in chemical reactions

Text Solution

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The correct Answer is:
To solve the question regarding why the dipole moment of \( H_2O_2 \) (hydrogen peroxide) is more than that of \( H_2O \) (water) but \( H_2O_2 \) is not a good solvent, we can break it down into the following steps: ### Step 1: Understand the dipole moment The dipole moment is a measure of the separation of positive and negative charges in a molecule. A higher dipole moment indicates a greater polarity. ### Step 2: Compare the dipole moments of \( H_2O \) and \( H_2O_2 \) - \( H_2O \) has a bent shape due to the two lone pairs on the oxygen atom, leading to a significant dipole moment. - \( H_2O_2 \) has a non-linear structure as well, but due to the presence of the O-O bond, it has a higher dipole moment than \( H_2O \). ### Step 3: Analyze the properties of \( H_2O_2 \) Despite having a higher dipole moment, \( H_2O_2 \) is not a good solvent. The reasons for this include: - **Thermal instability**: \( H_2O_2 \) decomposes easily into water and oxygen gas (reaction: \( 2 H_2O_2 \rightarrow 2 H_2O + O_2 \)). - **Oxidizing agent**: \( H_2O_2 \) has strong oxidizing properties due to the weak O-O bond, which allows it to release radicals and participate in redox reactions. ### Step 4: Conclusion The presence of weak bonds between the oxygen atoms in \( H_2O_2 \) makes it thermally unstable and a strong oxidizing agent. This instability and reactivity prevent \( H_2O_2 \) from being a good solvent, despite its higher dipole moment compared to \( H_2O \). ### Final Answer The dipole moment of \( H_2O_2 \) is more than that of \( H_2O \) because of its structure, but \( H_2O_2 \) is not a good solvent because it is thermally unstable and acts as a strong oxidizing agent. ---

To solve the question regarding why the dipole moment of \( H_2O_2 \) (hydrogen peroxide) is more than that of \( H_2O \) (water) but \( H_2O_2 \) is not a good solvent, we can break it down into the following steps: ### Step 1: Understand the dipole moment The dipole moment is a measure of the separation of positive and negative charges in a molecule. A higher dipole moment indicates a greater polarity. ### Step 2: Compare the dipole moments of \( H_2O \) and \( H_2O_2 \) - \( H_2O \) has a bent shape due to the two lone pairs on the oxygen atom, leading to a significant dipole moment. - \( H_2O_2 \) has a non-linear structure as well, but due to the presence of the O-O bond, it has a higher dipole moment than \( H_2O \). ...
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Knowledge Check

  • H_(2)O_(2) acts as a bleaching agent because of

    A
    reducing nature of `H_(2)O_(2)`
    B
    oxidising nature of `H_(2)O_(2)`
    C
    acidic nature of `H_(2)O_(2)`
    D
    basic nature of `H_(2)O_(2)`.
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    Explain why : dipole moment of H_2 O is much higher than that of H_2 S .

    Compare the stuctures of H_(2)O and H_(2)O_(2) .

    H_(2)O and H_(2)O_(2) resemble in

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    D_2O is more polar than H_2O.

    Statement-1: Dipole moment of H_(2)O is more than that of OF_(2) Statement-2: In H_(2)O , the resultant bond dipole of O-H bond and the resultant lone pair moment are in opposite direction.