Correct order of bond angle in given species is:

Options

A. `SiO_(4)^(4-) gt PCl_(3) gt NCl_(3) gt SbH_(3) gt H_(2) Te`
B. `SiO_(4)^(4-) gt NCl_(3) gt PCl_(3) gt SbH_(3) gt H_(2)Te`
C. `SiO_(4)^(4-) gt H_(2) Te gt SbH_(3) gt PCl_(3) gt NCl_(3)`
D. `NCl_(3) gt PCl_(3) gt SiO_(4)^(4-) gt SbH_(3) gt H_(2)Te`

Explanation

To determine the correct order of bond angles in the given species (SiO4^4-, BCl3, NCl3, SbH3, and H2Te), we will analyze each compound step by step based on their molecular geometry and the presence of lone pairs.

### Step 1: Analyze SiO4^4-
- **Geometry**: SiO4^4- has a tetrahedral geometry.
- **Bond Angle**: The bond angle in a perfect tetrahedral structure is approximately 109.5°.

### Step 2: Analyze BCl3
- **Geometry**: BCl3 has a trigonal planar geometry.
- **Bond Angle**: The bond angle in a trigonal planar structure is approximately 120°.

### Step 3: Analyze NCl3
- **Geometry**: NCl3 has a trigonal pyramidal geometry due to the presence of one lone pair on nitrogen.
- **Bond Angle**: The bond angle is less than 109.5° due to the repulsion from the lone pair, typically around 107°.

### Step 4: Analyze SbH3
- **Geometry**: SbH3 also has a trigonal pyramidal geometry with one lone pair on antimony.
- **Bond Angle**: Similar to NCl3, the bond angle is less than 109.5°, typically around 91.5°.

### Step 5: Analyze H2Te
- **Geometry**: H2Te has a bent shape due to two lone pairs on tellurium.
- **Bond Angle**: The bond angle is significantly smaller than 109.5°, typically around 104.5°.

### Summary of Bond Angles
1. **SiO4^4-**: 109.5°
2. **BCl3**: 120°
3. **NCl3**: ~107°
4. **SbH3**: ~91.5°
5. **H2Te**: ~104.5°

### Correct Order of Bond Angles
From the analysis, we can summarize the bond angles in descending order:
- **BCl3** (120°) > **SiO4^4-** (109.5°) > **NCl3** (~107°) > **H2Te** (~104.5°) > **SbH3** (~91.5°)

### Final Order
Thus, the correct order of bond angles in the given species is:
**BCl3 > SiO4^4- > NCl3 > H2Te > SbH3**