Which of the following statement(s) is/are correct about `SF_(4)` molecule?

Options

A. it has a square planar shape with S-atom having two lone pairs
B. It is hydrolysed by water to give `H_(2)SO_(3)` and HF as final products
C. During hydrolysis, S-atom in transition state is `sp^(3)d^(2)` hybridised
D. All S-F bond lengths are equal

Answer

To determine which statements about the `SF4` molecule are correct, we will analyze each statement step by step.

### Step 1: Determine the hybridization and shape of SF4
1. **Valence Electrons Calculation**:
- Sulfur (S) has 6 valence electrons.
- Each fluorine (F) atom has 1 valence electron, and there are 4 fluorine atoms.
- Total valence electrons = 6 (from S) + 4 (from F) = 10.

2. **Using the Hybridization Formula**:
- The formula for hybridization is:
\[ \text{Hybridization} = \frac{1}{2} \left( V + M - C \right) \]
where:
- \( V \) = number of valence electrons,
- \( M \) = number of monovalent atoms attached,
- \( C \) = charge (0 for neutral molecules).
- For SF4:
\[ \text{Hybridization} = \frac{1}{2} (6 + 4 + 0) = \frac{10}{2} = 5 \]
- This indicates that the hybridization is \( sp^3d \).

3. **Shape of SF4**:
- With 5 hybrid orbitals, and 4 bond pairs and 1 lone pair, the molecular geometry is a seesaw shape (not square planar).

### Step 2: Analyze the statements
1. **Statement 1**: "It has a square planar shape with sulfur atom having two lone pairs."
- **Analysis**: This statement is incorrect because SF4 has a seesaw shape due to one lone pair and four bond pairs.

2. **Statement 2**: "It is hydrolyzed with water to give H2SO3 and HF as final products."
- **Analysis**: This statement is correct. The hydrolysis of SF4 does lead to the formation of H2SO3 and HF.

3. **Statement 3**: "During hydrolysis, the sulfur atom in the transition state is sp3d2 hybridized."
- **Analysis**: This statement is correct. In the transition state during hydrolysis, the sulfur atom can be considered to have 5 bond pairs (4 fluorines and 1 water molecule) and 1 lone pair, leading to \( sp^3d^2 \) hybridization.

4. **Statement 4**: "All SF bond lengths are equal."
- **Analysis**: This statement is incorrect. The axial bonds in the seesaw structure are longer than the equatorial bonds due to increased repulsion.

### Conclusion
- The correct statements about SF4 are **Statement 2 and Statement 3**.

### Final Answer
The correct statements about SF4 are **2 and 3**.

---