Calculate value of "x+y" ffor "hypophoshporic acid", where x is total number of lone pair(s) and y is total number `pi`-bond(s) in givenn oxo-acids.

Explanation

To solve the problem of calculating the value of "x + y" for hypophosphoric acid (H4P2O6), where "x" is the total number of lone pairs and "y" is the total number of pi bonds, we can follow these steps:

### Step 1: Determine the Structure of Hypophosphoric Acid
Hypophosphoric acid has the formula H4P2O6. To understand its bonding and lone pairs, we need to visualize its structure. The structure consists of two phosphorus atoms (P) and six oxygen atoms (O), with hydroxyl (OH) groups attached.

### Step 2: Count the Lone Pairs
Each oxygen atom typically has two lone pairs of electrons. In hypophosphoric acid, there are six oxygen atoms. Therefore, the total number of lone pairs can be calculated as follows:
- Total oxygen atoms = 6
- Lone pairs per oxygen = 2
- Total lone pairs (x) = 6 × 2 = 12

### Step 3: Count the Pi Bonds
In the structure of hypophosphoric acid, we need to identify the pi bonds. A pi bond is formed when two p orbitals overlap. In the case of hypophosphoric acid:
- Each double bond between phosphorus and oxygen contributes one pi bond.
- There are two double bonds in the structure (P=O).
- Therefore, the total number of pi bonds (y) = 2.

### Step 4: Calculate x + y
Now that we have determined the values of x and y:
- x (total lone pairs) = 12
- y (total pi bonds) = 2
- Therefore, x + y = 12 + 2 = 14.

### Final Answer
The value of x + y for hypophosphoric acid is **14**.

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