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Which of the following species in neithe...

Which of the following species in neither hypervalent nor hypovalent ?

A

`ClO_(4)^(-)`

B

`BF_(3)`

C

`SO_(4)^(2-)`

D

`CO_(3)^(2-)`

Text Solution

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The correct Answer is:
To determine which of the given species is neither hypervalent nor hypovalent, we first need to understand the definitions of hypervalent and hypovalent species: 1. **Hypervalent Species**: These are species where the central atom has more than 8 electrons in its valence shell. 2. **Hypovalent Species**: These are species where the central atom has fewer than 8 electrons in its valence shell. Now, let's analyze each of the provided options: ### Step 1: Analyze ClO4⁻ (Chlorate Ion) - **Valence Electrons**: Chlorine (Cl) has 7 valence electrons, and each of the four oxygen (O) atoms contributes 6 valence electrons. The overall charge of -1 adds one more electron. - Total = 7 (Cl) + 4×6 (O) + 1 (charge) = 7 + 24 + 1 = 32 valence electrons. - In the Lewis structure, Cl is surrounded by 4 oxygen atoms, with double bonds to three of them and a single bond to one, resulting in 14 electrons around Cl. - **Conclusion**: ClO4⁻ is hypervalent (14 > 8). ### Step 2: Analyze BF3 (Boron Trifluoride) - **Valence Electrons**: Boron (B) has 3 valence electrons, and each of the three fluorine (F) atoms contributes 7 valence electrons. - Total = 3 (B) + 3×7 (F) = 3 + 21 = 24 valence electrons. - In the Lewis structure, B is surrounded by three F atoms, sharing 6 electrons total. - **Conclusion**: BF3 is hypovalent (6 < 8). ### Step 3: Analyze SO4²⁻ (Sulfate Ion) - **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each of the four oxygen (O) atoms contributes 6 valence electrons. The overall charge of -2 adds two more electrons. - Total = 6 (S) + 4×6 (O) + 2 (charge) = 6 + 24 + 2 = 32 valence electrons. - In the Lewis structure, S is surrounded by four oxygen atoms, with double bonds to two of them and single bonds to the others, resulting in 12 electrons around S. - **Conclusion**: SO4²⁻ is hypervalent (12 > 8). ### Step 4: Analyze CO3²⁻ (Carbonate Ion) - **Valence Electrons**: Carbon (C) has 4 valence electrons, and each of the three oxygen (O) atoms contributes 6 valence electrons. The overall charge of -2 adds two more electrons. - Total = 4 (C) + 3×6 (O) + 2 (charge) = 4 + 18 + 2 = 24 valence electrons. - In the Lewis structure, C is surrounded by three oxygen atoms, with one double bond and two single bonds, resulting in 8 electrons around C. - **Conclusion**: CO3²⁻ is neither hypervalent nor hypovalent (8 = 8). ### Final Answer: The species that is neither hypervalent nor hypovalent is **CO3²⁻ (Carbonate Ion)**.

To determine which of the given species is neither hypervalent nor hypovalent, we first need to understand the definitions of hypervalent and hypovalent species: 1. **Hypervalent Species**: These are species where the central atom has more than 8 electrons in its valence shell. 2. **Hypovalent Species**: These are species where the central atom has fewer than 8 electrons in its valence shell. Now, let's analyze each of the provided options: ### Step 1: Analyze ClO4⁻ (Chlorate Ion) ...
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